Python 如何在django中按列表过滤

我正在尝试按列表筛选查询集 我正在将unicode数据转换为1,4,5,6的格式

category = request.GET.getlist(category')
print type(category)



data = Leads.objects.filter(item_required__id= category ) 

那我就错了

invalid literal for int() with base 10: '1,4'

那么我该如何解决这个问题呢

Traceback:
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/core/handlers/base.py" in get_response
  132.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/views/decorators/csrf.py" in wrapped_view
  58.         return view_func(*args, **kwargs)
File "/home/cp/Documents/myshopup/markatix/customapi/vendors.py" in CustomerRequirements
  365.      cust_leads = CustomerLeads.objects.filter(item_required__id__in= category ).values('customer_name','budget','event','posting_date','quantity','other','fb_id','image','title').order_by('-posting_date')
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/manager.py" in manager_method
  127.                 return getattr(self.get_queryset(), name)(*args, **kwargs)
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/query.py" in filter
  679.         return self._filter_or_exclude(False, *args, **kwargs)
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/query.py" in _filter_or_exclude
  697.             clone.query.add_q(Q(*args, **kwargs))
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/sql/query.py" in add_q
  1310.         clause, require_inner = self._add_q(where_part, self.used_aliases)
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/sql/query.py" in _add_q
  1338.                     allow_joins=allow_joins, split_subq=split_subq,
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/sql/query.py" in build_filter
  1209.             condition = self.build_lookup(lookups, col, value)
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/sql/query.py" in build_lookup
  1102.                 return final_lookup(lhs, rhs)
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/lookups.py" in __init__
  105.         self.rhs = self.get_prep_lookup()
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/lookups.py" in get_prep_lookup
  143.         return self.lhs.output_field.get_prep_lookup(self.lookup_name, self.rhs)
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/fields/__init__.py" in get_prep_lookup
  729.             return [self.get_prep_value(v) for v in value]
File "/home/cp/Documents/envMyShopUp/local/lib/python2.7/site-packages/django/db/models/fields/__init__.py" in get_prep_value
  985.         return int(value)

Exception Type: ValueError at /customapi/vendor/customer-requirements/
Exception Value: invalid literal for int() with base 10: '1,4'

---

提前感谢。

我做了一些错误的步骤。最后我找到了解决方案

    category = request.GET.get('category')
l1=[]
    category_list =category.split(',')
    for i in category_list:
        a =int(i)
        l1.append(a)

cust_leads = CustomerLeads.objects.filter(item_required__id__in= l1 )

您还可以使用解析请求的查询参数列表：

from django.http.request import QueryDict

query = QueryDict('category=1&category=2')
categories = query.getlist('category')  # -> ['1', '2']
leads = Leads.objects.filter(item_required__id__in=categories)

通过这种方式，用户可以通过将类别逐个添加到查询中来为您提供类别列表。这个解决方案对您来说可能已经足够好了

但是，您的用户（或您）可能希望提供免费样式列表，并且在您的查询中可能有多个。在这种情况下，您必须获取所有列表，这些列表可以是主键列表，并将它们映射到可用于Django筛选器的平面列表

from itertools import chain
from django.http.request import QueryDict

query = QueryDict('categories=1,2,3&categories=4,5')
categories_strings = query.getlist('categories')  # -> ['1,2,3', '4,5']
categories = list(chain.from_iterable(
    map(lambda categories: categories.split(','), categories_strings))
)  # -> ['1', '2', '3', '4', '5']
leads = Leads.objects.filter(item_required__id__in=categories)

幸运的是，您可以轻松地将其写入一个简洁的小函数：

# Your myapp/utils.py module
from itertools import chain

# Python 3.5+ type type annotated function, you can use
# this without the type annotations in Python 2.7 as well
def get_query_list(querydict: QueryDict, key: str) -> list:
    return list(chain.from_iterable(
        map(lambda query: query.split(','), querydict.getlist(key)))
    )

这就是它的工作原理：

from django.http.request import QueryDict
from myapp.utils import get_query_list

q = QueryDict('a=1&a=2&a=3,4')
get_query_list(q, 'a')  # -> ['1', '2', '3', '4']

您可以从视图中使用它：

# Your myapp/views.py module
from myapp.utils import get_query_list

def my_view(request):
    categories = get_query_list(request.GET, 'categories')  # or 'category'
    # ...

这是一种更详细的方式，而不是使用单一的查询参数来代替列表，并且支持多种不同的格式

根据需要添加类型组合：

def my_view(request):
    # A nice and neat one-liner
    categories = get_query_list(request.GET, 'categories')  # or 'category'
    for item in categories:
        try:
            assert int(item)
        except ValueError:
            raise ValidationError('{} is not of correct type {}'.format(item, int))
    # Everything should be parsed and validated
    leads = Leads.objects.filter(item_required__id__in=categories)

---

Django在实现搜索或通用过滤器时经常需要这种方法。

它不是一个单独项目的列表，而是一个包含字符串

1,4

的列表

getlist

希望您像在

category=1和category=4中那样传递参数