Python 如果循环在返回后未结束

各位委员:

我已经绞尽脑汁好几个小时了，为什么我的代码不起作用

我从CSV文件中获取数据，当两个代码匹配时，我尝试更改一个值

def mode(x):
for line in data_df['Bar_Code']:
    #print(line) ~ Line outputs the Barcodes in the Bar_Code Column of the CSV file.
    with open("Barcodes_to_match.txt") as barcodes:
        for barcode in barcodes:
            #print(barcode) ~ Outputs the Barcode that it need to be matched.
            if barcode == line:
                x = x.replace("True", "False")
                return x

data_df['Published'] = data_df['Published'].apply(lambda x: mode(x))

data_df.to_csv(('Products.csv'), encoding='UTF-8', quoting=csv.QUOTE_ALL, quotechar='"', index=None, sep=str(","))

Product.csv文件：

Bar_Code, Product, Published
BLA00BLA00, Product1, True
BLU00BLU00, Product2, False
BLI00BLI00, Product3, True
BLE00BLE00, Product4, False

条形码_至_match.txt：

BLA00BLA00
BLI00BLI00

因此，我需要将Product rowsBLA00BLA00和BLI00BLI00 Published列的值更改为False

有人可以检查我的方法来替换这些值吗

谢谢

编辑： 当我添加print命令时，代码似乎在无限循环的最后一次匹配中存储

if barcode == line:
   print(barcode + " = " + line)
   x = x.replace("True", "False")
   return x

Output:
BLI00BLI00 = BLI00BLI00
BLI00BLI00 = BLI00BLI00
BLI00BLI00 = BLI00BLI00
BLI00BLI00 = BLI00BLI00
BLI00BLI00 = BLI00BLI00
BLI00BLI00 = BLI00BLI00
BLI00BLI00 = BLI00BLI00
BLI00BLI00 = BLI00BLI00

---

我无法运行您的代码，要实现您想要的，请尝试以下操作：

import csv
import pandas as pd

data_df = pd.read_csv('Products.csv')
print(data_df)

with open("Barcodes_to_match.txt") as f:
    barcodes = f.read().splitlines()

data_df.loc[data_df['Bar_Code'].isin(barcodes), 'Published'] = False

print(data_df)

data_df.to_csv(('Products.csv'), encoding='UTF-8', quoting=csv.QUOTE_ALL, quotechar='"', index=None, sep=str(","))

Products.csv

"Bar_Code","Product","Published"
"BLA00BLA00","Product1","False"
"BLU00BLU00","Product2","False"
"BLI00BLI00","Product3","False"
"BLE00BLE00","Product4","False"

---

如果返回后循环未结束？这是一个矛盾。返回退出函数；此后循环将无法再运行。请参阅有关函数的任何教程。如果您需要更多帮助，请提供一个。该代码应该做什么？