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用于测试最近修改的文件的Python脚本-结果不一致_Python_File_Testing_Directory - Fatal编程技术网

用于测试最近修改的文件的Python脚本-结果不一致

用于测试最近修改的文件的Python脚本-结果不一致,python,file,testing,directory,Python,File,Testing,Directory,我在stackoverflow上找到了这篇文章,这正是我想要集成到我正在编写的更大脚本中的内容: 我想检查最新的文件或文件夹,以便对脚本进行如下修改: #!/usr/bin/env python3.1 import os def allFilesIn(b='.'): result = [] for d in os.listdir(b): bd = os.path.join(b, d) result.append(bd) return resul

我在stackoverflow上找到了这篇文章,这正是我想要集成到我正在编写的更大脚本中的内容:

我想检查最新的文件或文件夹,以便对脚本进行如下修改:

#!/usr/bin/env python3.1

import os

def allFilesIn(b='.'):
    result = []
    for d in os.listdir(b):
        bd = os.path.join(b, d)
    result.append(bd)
    return result

latest_subdir = max(allFilesIn('/tmp/testforlatest'), key=os.path.getmtime)

print(latest_subdir)
> touch /tmp/testforlatest/file1
> ls -t -1 /tmp/testforlatest/ | head -1
file1
> /tmp/testfornewestfile.py 
/tmp/testforlatest/file1
> touch /tmp/testforlatest/file2
> ls -t -1 /tmp/testforlatest/ | head -1
file2
> /tmp/testfornewestfile.py 
/tmp/testforlatest/file1
> mkdir /tmp/testforlatest/folder1
> ls -t -1 /tmp/testforlatest/ | head -1
folder1/
> /tmp/testfornewestfile.py 
/tmp/testforlatest/folder1
> mkdir /tmp/testforlatest/folder2
> ls -t -1 /tmp/testforlatest/ | head -1
folder2/
> /tmp/testfornewestfile.py 
/tmp/testforlatest/folder1
> touch /tmp/testforlatest/file3
> ls -t -1 /tmp/testforlatest/ | head -1
file3
> /tmp/testfornewestfile.py 
/tmp/testforlatest/folder1
然而,我得到的结果如下:

#!/usr/bin/env python3.1

import os

def allFilesIn(b='.'):
    result = []
    for d in os.listdir(b):
        bd = os.path.join(b, d)
    result.append(bd)
    return result

latest_subdir = max(allFilesIn('/tmp/testforlatest'), key=os.path.getmtime)

print(latest_subdir)
> touch /tmp/testforlatest/file1
> ls -t -1 /tmp/testforlatest/ | head -1
file1
> /tmp/testfornewestfile.py 
/tmp/testforlatest/file1
> touch /tmp/testforlatest/file2
> ls -t -1 /tmp/testforlatest/ | head -1
file2
> /tmp/testfornewestfile.py 
/tmp/testforlatest/file1
> mkdir /tmp/testforlatest/folder1
> ls -t -1 /tmp/testforlatest/ | head -1
folder1/
> /tmp/testfornewestfile.py 
/tmp/testforlatest/folder1
> mkdir /tmp/testforlatest/folder2
> ls -t -1 /tmp/testforlatest/ | head -1
folder2/
> /tmp/testfornewestfile.py 
/tmp/testforlatest/folder1
> touch /tmp/testforlatest/file3
> ls -t -1 /tmp/testforlatest/ | head -1
file3
> /tmp/testfornewestfile.py 
/tmp/testforlatest/folder1
有人能解释一下为什么会这样,我做错了什么吗

其他可能有用的信息:

> python3.1 --version
Python 3.1.3
> cat /etc/debian_version 
6.0.2

函数
allFilesIn
只返回由
os.listdir
返回的最后一个文件,因为您将结果附加到for循环之外。你可能是这个意思:

def allFilesIn(b='.'):
    result = []
    for d in os.listdir(b):
        bd = os.path.join(b, d)
        result.append(bd)
    return result
另一方面,最好对每个函数名使用小写和下划线。您还可以很容易地将函数压缩为列表:

def all_files_in(path='.'):
    return [os.path.join(path, f) for f in os.listdir(path)]

谢谢zeekay,这很有效-我知道在将来事情不起作用时检查我的缩进。也谢谢你给PEP8的链接,谢谢。