Python TypeError:\uuuu init\uuuuuuu（）接受1个位置参数，但给出了2个，通知bot用于不一致

我的bot在运行命令和idk时出现问题，为什么它一直给我这个错误，我使用的bot是为了发布discord，所以我在bot中使用的代码如下：

import discord
from discord.ext import commands
from discord.ext.commands import Bot
import asyncio
import time
from discord.ext.commands import has_permissions

client = commands.Bot(command_prefix = "+")
client.remove_command("help")

@client.event
async def on_ready():
   print(client.user.name)
   print("Online")
   print("-------")

@client.command(pass_context=True)
async def announce(ctx,*,message):
    embed = discord.Embed("Information",description=message,color=0x9200ea)
    embed.set_footer(text="Made by Elanovic#7940")
    await client.send_message(ctx.message.channel,embed=embed)

client.run("TOKEN")

这是我从命令中得到的错误：

Ignoring exception in command announce:
Traceback (most recent call last):
File "C:\Users\Hasanfox69\AppData\Local\Programs\Python\Python39\lib\site-packages\discord\ext\commands\core.py", line 85, in wrapped
    ret = await coro(*args, **kwargs)
  File "C:\Users\Hasanfox69\Desktop\PYTHON\bot.py", line 19, in announce
    embed = discord.Embed("Information",description=message,color=0x9200ea)
TypeError: __init__() takes 1 positional argument but 2 were given


The above exception was the direct cause of the following exception:

Traceback (most recent call last):
  File "C:\Users\Hasanfox69\AppData\Local\Programs\Python\Python39\lib\site-packages\discord\ext\commands\bot.py", line 939, in invoke
    await ctx.command.invoke(ctx)
  File "C:\Users\Hasanfox69\AppData\Local\Programs\Python\Python39\lib\site-packages\discord\ext\commands\core.py", line 863, in invoke
    await injected(*ctx.args, **ctx.kwargs)
  File "C:\Users\Hasanfox69\AppData\Local\Programs\Python\Python39\lib\site-packages\discord\ext\commands\core.py", line 94, in wrapped
    raise CommandInvokeError(exc) from exc
discord.ext.commands.errors.CommandInvokeError: Command raised an exception: TypeError: __init__() takes 1 positional argument but 2 were given

所有这些都发生在cmd中，bot通过命令

+annound

从discord频道接收命令

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但是bot会在cmd中响应上面的命令。代码中的错误是一个简单命令的属性错误

嵌入的语法为：

discord.Embed(Name="Embed", description='This is an EMBED', color=0xff00ff)

代码中的错误在哪里？ 错误在嵌入代码中，也可以在回溯中看到

embed = discord.Embed("Information",description=message,color=0x9200ea)

您必须尝试输入嵌入的名称，但没有正确写入

因此，我只想说，将这一行更改为：

discord.Embed(name='Information', description=message, color=0x9200ea)

这将彻底解决你的问题

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最后，我给你一个简单的建议。始终检查错误的回溯。在回溯中，您可以看到：

1.File "C:\Users\Hasanfox69\AppData\Local\Programs\Python\Python39\lib\site-packages\discord\ext\commands\core.py", line 85, in wrapped
2.    ret = await coro(*args, **kwargs)
3.  File "C:\Users\Hasanfox69\Desktop\PYTHON\bot.py", line 19, in announce
4.    embed = discord.Embed("Information",description=message,color=0x9200ea)
    TypeError: __init__() takes 1 positional argument but 2 were given

第4行（根据我的标记）显示错误在嵌入代码中，因此您只需知道它来自何处，就可以简单地解决它

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我很高兴能帮上忙。请随时询问您是否还有任何问题。：）

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谢谢D

discord.Embed的参数不接受字符串作为第一个参数，并且列出的属性名称是color，而不是color