Warning: file_get_contents(/data/phpspider/zhask/data//catemap/2/python/361.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
如何在Python中将混合值转换为整数?_Python_Pandas_Dataframe_Types - Fatal编程技术网

如何在Python中将混合值转换为整数?

如何在Python中将混合值转换为整数?,python,pandas,dataframe,types,Python,Pandas,Dataframe,Types,我在DataFrame中有一列,如下所示: column1 Jone Jeck 42 Fin Tom 45 所有值都是str。如何将42和45转换为int类型?使用自定义函数,但以后实际处理混合数据确实很痛苦: def f(x): try: return int(x) except: return x df['column1'] = df['column1'].apply(f) print (df) column1 0 Jone 1

我在DataFrame中有一列,如下所示:

column1
Jone
Jeck
42
Fin
Tom
45

所有值都是str。如何将42和45转换为int类型?

使用自定义函数,但以后实际处理混合数据确实很痛苦:

def f(x):
    try:
        return int(x)
    except:
        return x

df['column1'] = df['column1'].apply(f)
print (df)
  column1
0    Jone
1    Jeck
2      42
3     Fin
4     Tom
5      45

print (df['column1'].apply(type))
0    <class 'str'>
1    <class 'str'>
2    <class 'int'>
3    <class 'str'>
4    <class 'str'>
5    <class 'int'>
Name: column1, dtype: object
def(x):
尝试:
返回整数(x)
除:
返回x
df['column1']=df['column1'].应用(f)
打印(df)
专栏1
0琼斯
1杰克
2      42
3鳍
4汤姆
5      45
打印(df['column1'].应用(类型))
0
1.
2.
3.
4.
5.
名称:column1,数据类型:object

使用自定义函数,但以后实际处理混合数据确实很痛苦:

def f(x):
    try:
        return int(x)
    except:
        return x

df['column1'] = df['column1'].apply(f)
print (df)
  column1
0    Jone
1    Jeck
2      42
3     Fin
4     Tom
5      45

print (df['column1'].apply(type))
0    <class 'str'>
1    <class 'str'>
2    <class 'int'>
3    <class 'str'>
4    <class 'str'>
5    <class 'int'>
Name: column1, dtype: object
def(x):
尝试:
返回整数(x)
除:
返回x
df['column1']=df['column1'].应用(f)
打印(df)
专栏1
0琼斯
1杰克
2      42
3鳍
4汤姆
5      45
打印(df['column1'].应用(类型))
0
1.
2.
3.
4.
5.
名称:column1,数据类型:object
val='42';int(val)?val='42';int(val)?