使用stringr查找和替换字符串

我试图找到并替换由字符串组成的数据帧的一些值。简单的例子如下：

library(stringr)
test1 <- c("one", "two", "three")
str_replace_all(string = test1,
                pattern = c('one' = "1ne",
                            'three' = "3ree"))
> [1] "1ne"  "two"  "3ree"

然而，像下面这样一个更复杂的案例是行不通的。我做错了什么

test2 <- c("one (1) x1", "two (2) x2", "three (3) x3")
test2 <- c("one (1) x1", "two (2) x2", "three (3) x3")
str_replace_all(string = test2,
                   pattern = c('one (1) x1' = "X1",
                               'two (2) x2' = "X2"))
> [1] "one (1) x1"   "two (2) x2"   "three (3) x3"

---

使用fixed避免正则表达式匹配

str_replace_all(string = test2,
                pattern = fixed(c('one (1) x1' = "X1",
                          'two (2) x2' = "X2")))
# [1] "X1"           "X2"           "three (3) x3"

---

在模式中使用大括号之前，请尝试使用“\\”，例如一个\\1\\x1str\u替换\u所有使用正则表达式和圆括号都不会被解释为圆括号。在正则表达式中，圆括号有特殊含义。您需要对其进行转义或使用fixed。可能重复