R 插补中间缺失值
我有一组级别的数据。外观如下所示 I实际数据为“值”&所需数据为“预期值” 我尝试了以下代码:R 插补中间缺失值,r,data.table,zoo,R,Data.table,Zoo,我有一组级别的数据。外观如下所示 I实际数据为“值”&所需数据为“预期值” 我尝试了以下代码: setDT(file_to_share)[,Expected_Value := na.locf(na.locf(Value, na.rm=FALSE), fromLast=TRUE),by = c("Group_A", "Group_B")] 但在该代码中,插补是对整个缺失值进行的。如果缺失值介于两个值之间,我想计算缺失值。缺少的值将是以前可用值的复制 如果有人能指导我怎么做,那将是一个很大的帮
setDT(file_to_share)[,Expected_Value := na.locf(na.locf(Value, na.rm=FALSE), fromLast=TRUE),by = c("Group_A", "Group_B")]
但在该代码中,插补是对整个缺失值进行的。如果缺失值介于两个值之间,我想计算缺失值。缺少的值将是以前可用值的复制
如果有人能指导我怎么做,那将是一个很大的帮助
注意:我试图使用
数据进行计算。表
和动物园
。但任何其他方法都可以 即使您正在寻找一个data.table
解决方案,下面是一个使用tidyverse
方法的解决方案。(如果时间允许,我可能会尝试翻译成data.table
)
我们的想法是创建一个分组变量来捕获您的周数,并在分组a、分组B和分组周(此处称为grp
)下填充值。我们还创建了Value
到fill
fromlast(tidyr
术语为。direction='up'
)的副本。然后,我们用NA
值的累积和创建另一个分组变量,并将Value
列中的值替换为NA
,前提是新的组大小(groupa
,groupb
,grp
和grp1
)为1,其Value 1
为NA
。这就给出了预期的结果
library(tidyverse)
df2 <- df1 %>%
mutate(Date = as.POSIXct(Date, format = '%m/%d/%Y')) %>%
mutate(value1 = Value) %>%
group_by(Group_A, GROUP_B, grp = cumsum(format(Date, '%d')=='01'))%>%
fill(Value) %>%
fill(value1, .direction = 'up') %>%
mutate(grp1 = cumsum(is.na(Value))) %>%
group_by(Group_A, GROUP_B, grp, grp1) %>%
mutate(new = n(), Value = replace(Value, new == 1 | is.na(value1), NA)) %>%
ungroup() %>%
select(-c(value1, grp, grp1, new))
OP已要求仅填写NA
值,这些值位于各组内其他值之间。这意味着在应用zoo::NA.locf()
时,跳过每组开始或结束处的任何NA
值序列
使用data.table
,可以通过标识要跳过的行的索引和一种反连接来完成此操作:
解释
- 对于每组,
NA
/非NA
值的条纹进行编号
- 将拾取每组中的第一个和最后一个条纹,并从特殊符号
.I
检索索引。(由于值
将就地更新,因此第一条或最后一条条纹是否包含NA
并不重要;它们无论如何都不会更新。)
- 找到的索引
DT[,,{na_grp尝试tidyr中的完整功能?@reuben:谢谢你的评论。不,我没有尝试tidyr。行21:23
不应该也被填充吗?@Sotos:不。在第2组X第1组中,什么都不会被填充。那是因为“值”之间没有遗漏。我专门创建了这个示例来更好地突出我的问题。谢谢!美化书面回答。它满足了我的所有要求。谢谢!我通常不会改变我的标记答案。但不幸的是,我们的答案与我接近的方式非常相似。所以我不得不改变主意。但非常感谢你的答案。同样棒极了!!我还高估了你的一些答案。它们同样非常好。N问题。谢谢:)
# A tibble: 42 × 5
Group_A GROUP_B Date Value Expected_Value
<chr> <chr> <dttm> <int> <int>
1 GROUP_1 Group_1_1 2017-01-01 NA NA
2 GROUP_1 Group_1_1 2017-01-02 NA NA
3 GROUP_1 Group_1_1 2017-01-03 34 34
4 GROUP_1 Group_1_1 2017-01-04 20 20
5 GROUP_1 Group_1_1 2017-01-05 20 20
6 GROUP_1 Group_1_1 2017-01-06 20 20
7 GROUP_1 Group_1_1 2017-01-07 38 38
8 GROUP_1 Group_1_2 2017-01-01 35 35
9 GROUP_1 Group_1_2 2017-01-02 28 28
10 GROUP_1 Group_1_2 2017-01-03 28 28
# ... with 32 more rows
#Where,
identical(df2$Value, df2$Expected_Value)
#[1] TRUE
library(data.table)
setDT(DT)[!DT[, {
na_grp <- rleid(is.na(Value))
.I[na_grp %in% c(1L, max(na_grp))]
}, by = .(Group_A, GROUP_B)]$V1, Value := zoo::na.locf(Value)][]
Group_A GROUP_B Date Value Expected_Value
1: GROUP_1 Group_1_1 1/1/2017 NA NA
2: GROUP_1 Group_1_1 1/2/2017 NA NA
3: GROUP_1 Group_1_1 1/3/2017 34 34
4: GROUP_1 Group_1_1 1/4/2017 20 20
5: GROUP_1 Group_1_1 1/5/2017 20 20
6: GROUP_1 Group_1_1 1/6/2017 20 20
7: GROUP_1 Group_1_1 1/7/2017 38 38
8: GROUP_1 Group_1_2 1/1/2017 35 35
9: GROUP_1 Group_1_2 1/2/2017 28 28
10: GROUP_1 Group_1_2 1/3/2017 20 28
11: GROUP_1 Group_1_2 1/4/2017 32 32
12: GROUP_1 Group_1_2 1/5/2017 39 39
13: GROUP_1 Group_1_2 1/6/2017 28 28
14: GROUP_1 Group_1_2 1/7/2017 NA NA
15: GROUP_2 Group_1_11 1/1/2017 NA NA
16: GROUP_2 Group_1_11 1/2/2017 NA NA
17: GROUP_2 Group_1_11 1/3/2017 40 40
18: GROUP_2 Group_1_11 1/4/2017 32 32
19: GROUP_2 Group_1_11 1/5/2017 20 20
20: GROUP_2 Group_1_11 1/6/2017 NA NA
21: GROUP_2 Group_1_11 1/7/2017 NA NA
22: GROUP_2 Group_1_21 1/1/2017 NA NA
23: GROUP_2 Group_1_21 1/2/2017 32 32
24: GROUP_2 Group_1_21 1/3/2017 36 36
25: GROUP_2 Group_1_21 1/4/2017 36 36
26: GROUP_2 Group_1_21 1/5/2017 28 28
27: GROUP_2 Group_1_21 1/6/2017 33 33
28: GROUP_2 Group_1_21 1/7/2017 40 40
29: GROUP_3 Group_1_13 1/1/2017 NA NA
30: GROUP_3 Group_1_13 1/2/2017 NA NA
31: GROUP_3 Group_1_13 1/3/2017 NA NA
32: GROUP_3 Group_1_13 1/4/2017 29 29
33: GROUP_3 Group_1_13 1/5/2017 31 31
34: GROUP_3 Group_1_13 1/6/2017 31 31
35: GROUP_3 Group_1_13 1/7/2017 34 34
36: GROUP_3 Group_1_23 1/1/2017 26 26
37: GROUP_3 Group_1_23 1/2/2017 33 33
38: GROUP_3 Group_1_23 1/3/2017 27 27
39: GROUP_3 Group_1_23 1/4/2017 23 23
40: GROUP_3 Group_1_23 1/5/2017 25 25
41: GROUP_3 Group_1_23 1/6/2017 41 41
42: GROUP_3 Group_1_23 1/7/2017 25 25
Group_A GROUP_B Date Value Expected_Value
DT <- structure(list(Group_A = c("GROUP_1", "GROUP_1", "GROUP_1", "GROUP_1",
"GROUP_1", "GROUP_1", "GROUP_1", "GROUP_1", "GROUP_1", "GROUP_1",
"GROUP_1", "GROUP_1", "GROUP_1", "GROUP_1", "GROUP_2", "GROUP_2",
"GROUP_2", "GROUP_2", "GROUP_2", "GROUP_2", "GROUP_2", "GROUP_2",
"GROUP_2", "GROUP_2", "GROUP_2", "GROUP_2", "GROUP_2", "GROUP_2",
"GROUP_3", "GROUP_3", "GROUP_3", "GROUP_3", "GROUP_3", "GROUP_3",
"GROUP_3", "GROUP_3", "GROUP_3", "GROUP_3", "GROUP_3", "GROUP_3",
"GROUP_3", "GROUP_3"), GROUP_B = c("Group_1_1", "Group_1_1",
"Group_1_1", "Group_1_1", "Group_1_1", "Group_1_1", "Group_1_1",
"Group_1_2", "Group_1_2", "Group_1_2", "Group_1_2", "Group_1_2",
"Group_1_2", "Group_1_2", "Group_1_11", "Group_1_11", "Group_1_11",
"Group_1_11", "Group_1_11", "Group_1_11", "Group_1_11", "Group_1_21",
"Group_1_21", "Group_1_21", "Group_1_21", "Group_1_21", "Group_1_21",
"Group_1_21", "Group_1_13", "Group_1_13", "Group_1_13", "Group_1_13",
"Group_1_13", "Group_1_13", "Group_1_13", "Group_1_23", "Group_1_23",
"Group_1_23", "Group_1_23", "Group_1_23", "Group_1_23", "Group_1_23"
), Date = c("1/1/2017", "1/2/2017", "1/3/2017", "1/4/2017", "1/5/2017",
"1/6/2017", "1/7/2017", "1/1/2017", "1/2/2017", "1/3/2017", "1/4/2017",
"1/5/2017", "1/6/2017", "1/7/2017", "1/1/2017", "1/2/2017", "1/3/2017",
"1/4/2017", "1/5/2017", "1/6/2017", "1/7/2017", "1/1/2017", "1/2/2017",
"1/3/2017", "1/4/2017", "1/5/2017", "1/6/2017", "1/7/2017", "1/1/2017",
"1/2/2017", "1/3/2017", "1/4/2017", "1/5/2017", "1/6/2017", "1/7/2017",
"1/1/2017", "1/2/2017", "1/3/2017", "1/4/2017", "1/5/2017", "1/6/2017",
"1/7/2017"), Value = c(NA, NA, 34L, 20L, NA, NA, 38L, 35L, 28L,
NA, 32L, 39L, 28L, NA, NA, NA, 40L, 32L, 20L, NA, NA, NA, 32L,
36L, NA, 28L, 33L, 40L, NA, NA, NA, 29L, 31L, NA, 34L, 26L, 33L,
27L, 23L, 25L, 41L, 25L), Expected_Value = c(NA, NA, 34L, 20L,
20L, 20L, 38L, 35L, 28L, 28L, 32L, 39L, 28L, NA, NA, NA, 40L,
32L, 20L, NA, NA, NA, 32L, 36L, 36L, 28L, 33L, 40L, NA, NA, NA,
29L, 31L, 31L, 34L, 26L, 33L, 27L, 23L, 25L, 41L, 25L)), .Names = c("Group_A",
"GROUP_B", "Date", "Value", "Expected_Value"), row.names = c(NA,
-42L), class = "data.frame")