R 将数据帧列作为参数传递给mutate函数
我有一个表,有五列,分别是年份、GDP、收入、收入和工资。我用下面的代码计算了这个表R 将数据帧列作为参数传递给mutate函数,r,function,dplyr,tidyeval,R,Function,Dplyr,Tidyeval,我有一个表,有五列,分别是年份、GDP、收入、收入和工资。我用下面的代码计算了这个表 library(dplyr) #DATA TEST<-data.frame( Year= c(2000,2001,2002,2003,2004,2005,2006,2007,2008,2009,2010,2011,2012,2013,2014,2015,2016,2017,2018,2019,2020,2021), GDP =c(8634,5798,6022,6002,6266,6478,673
library(dplyr)
#DATA
TEST<-data.frame(
Year= c(2000,2001,2002,2003,2004,2005,2006,2007,2008,2009,2010,2011,2012,2013,2014,2015,2016,2017,2018,2019,2020,2021),
GDP =c(8634,5798,6022,6002,6266,6478,6732,7224,6956,6968,7098,7620,7642,8203,9856,20328,22364,22222,23250,25250,26250,27250),
Revenue =c(8734,5798,7011,7002,7177,7478,7731,7114,7957,7978,7098,7710,7742,8203,9857,10328,11374,12211,13150,15150,17150,17150),
Income =c(8834,5898,6033,6002,6366,6488,6833,8334,6956,6968,8098,8630,8642,8203,9856,30328,33364,32233,33350,35350,36350,38350),
Wages =c(8834,5598,8044,8002,8488,8458,8534,5444,8958,8988,5098,5840,5842,8203,9858,40328,44384,42244,43450,45450,48450,45450)
)
#CALCULATION
ESTIMATION_0<-data.frame(mutate(TEST,
ETR_Revenue=(Revenue/GDP),
ETR_Income=(Income/GDP),
ETR_Wages=(Wages/GDP)
))
View(ESTIMATION_0)
库(dplyr)
#资料
使用类似于此的整洁评估方法进行测试
库(rlang)
图书馆(tidyverse)
我的估计年度GDP收入收入工资ETR收入ETR收入ETR收入ETR工资
#>
#> 1 2000 8634 8734 8834 8834 1.01 1.02 1.02
#> 2 2001 5798 5798 5898 5598 1 1.02 0.966
#> 3 2002 6022 7011 6033 8044 1.16 1.00 1.34
#> 4 2003 6002 7002 6002 8002 1.17 1 1.33
#> 5 2004 6266 7177 6366 8488 1.15 1.02 1.35
#> 6 2005 6478 7478 6488 8458 1.15 1.00 1.31
#> 7 2006 6732 7731 6833 8534 1.15 1.02 1.27
#> 8 2007 7224 7114 8334 5444 0.985 1.15 0.754
#> 9 2008 6956 7957 6956 8958 1.14 1 1.29
#> 10 2009 6968 7978 6968 8988 1.14 1 1.29
#> # ... 还有12排
由(v0.2.1.9000)于2019-03-01创建的您的意思是编写类似于fun2的内容也很有用:&