R 在执行用户定义的函数后，我得到一个错误

我在印度有27个州，必须测试和绘制水质图

state_1 <- subset(train,train$State.Name=="ANDHRA PRADESH")
ANDHRA <- as.data.frame(table(state_1$District.Name,state_1$Quality.Parameter,state_1$Year),stringsAsFactors = FALSE)
str(ANDHRA)
names(ANDHRA) <- c("District.Name","CHEMICAL","YEAR")
an <- ggplot(ANDHRA,aes(ANDHRA$CHEMICAL,ANDHRA$Freq,fill=ANDHRA$District.Name))
an+geom_bar(stat="identity",position = "dodge")+facet_grid(.~ANDHRA$YEAR)+
labs(title="TREND of Chemical Compostion in Andhra Pradesh Villages",x="Chemicals",y="Number Of Cases",fill="Districts in Andhra Pradesh")

原因可能是什么

已编辑

------现在是错误------

---

似乎它没有将“喀拉拉”识别为物体。

错误是直截了当的。您需要定义3个名称，而不是4个（我没有看到您正在创建的表中的

CHEMICAL

/

Freq

），如错误所示，“d”中的列数为3，而传递的是4个元素的向量作为

名称

字符串和引号有很多问题-在函数中，

有：train$State.Name==“a”

可能需要a的地方。另外，你可能应该引用你的“喀拉拉”输入，你是绝对正确的，但是当我用双引号传递参数时。我得到了一个没有任何内容的图。你能检查一下代码吗。我相信标题标签也没有返回值是的，我已经编辑过了。现在它无法识别我通过的州名称。请帮助。

district_analysis<-function(a,b,d) {
b<- subset(train,train$State.Name=="a")
d<- as.data.frame(table(b$District.Name,b$Quality.Parameter,b$Year),stringsAsFactors = FALSE)
names(d) <- c("District.Name","CHEMICAL","YEAR")
an <- ggplot(d,aes(d$CHEMICAL,d$Freq,fill=d$District.Name))
an+geom_bar(stat="identity",position = "dodge")+facet_grid(.~d$YEAR)+labs(title=paste0("TREND of Chemical Compostion in ", a, " Villages"),x="Chemicals",y="Number Of Cases",fill=paste0("Districts in", a)) 
return(an) }

> district_analysis(KERALA,bb,dd)
Error in labs(title = "TREND of Chemical Compostion in ", a, " Villages",  : 
object 'KERALA' not found
Called from: labs(title = "TREND of Chemical Compostion in ", a, " Villages", 
x = "Chemicals", y = "Number Of Cases", fill = "Districts in", 
a)
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