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如何在R中解释双向方差分析表(lmer)的输出?_R_Lme4_Anova - Fatal编程技术网

如何在R中解释双向方差分析表(lmer)的输出?

如何在R中解释双向方差分析表(lmer)的输出?,r,lme4,anova,R,Lme4,Anova,我有一个2 x 2的析因设计(“密度”,“肥料”),以块为随机效应。我试图预测植物的生长。我如何解释这张表?我已经检查过了,没有交互作用,它遵循方差分析的假设 Sample data: density <- c("low","low","low","low","high",high",high","high") fertilizer <- c("N","N","P","P","N","N","P","P") growth <

我有一个2 x 2的析因设计(“密度”,“肥料”),以块为随机效应。我试图预测植物的生长。我如何解释这张表?我已经检查过了,没有交互作用,它遵循方差分析的假设

   Sample data: 
        density <- c("low","low","low","low","high",high",high","high")
        fertilizer <- c("N","N","P","P","N","N","P","P")
        growth <- c(1,1,2,2,5,6,2,1)

    model <- lmer(growth~density + fertilizer + (1|block))


        Output:

        Fixed effects:
                 Estimate Std. Error       df t value Pr(>|t|)    
    (Intercept)   0.63351    0.06275 62.79670  10.096 8.92e-15 ***
    densityHigh   0.12473    0.07502 85.99111   1.663    0.100    
    fertlizerP    0.01209    0.00602 76.42369   0.422    0.005 ** 
示例数据:

密度N与p不同,与密度水平无关,或2x2设计的精度更高:N与p的密度平均值不同。或者:如果密度保持不变,肥料从N改为P,则生长增加0.012


而且

虽然这应该是交叉验证,但data.frame中的块是什么?