R 按季度频率从字符转换时间变量
我有一个季度频率和3个时间变量的数据框架,时间是一个字符变量。数据框如下所示R 按季度频率从字符转换时间变量,r,dataframe,data-manipulation,R,Dataframe,Data Manipulation,我有一个季度频率和3个时间变量的数据框架,时间是一个字符变量。数据框如下所示 dt <- structure(list( name1 = c("C","C","C","C","C","C","B","B","B","B","B","B"), name2 = c("D","E","A","D","E","A","D","E","A","D","E","A"), year = c(2012, 2012, 201
dt <- structure(list(
name1 = c("C","C","C","C","C","C","B","B","B","B","B","B"),
name2 = c("D","E","A","D","E","A","D","E","A","D","E","A"),
year = c(2012, 2012, 2012, 2010, 2010, 2010, 2012, 2012, 2012, 2010, 2010, 2010 ),
quarter = c(4,4,4,1,1,1,4,4,4,1,1,1),
time = c("2012q4", "2012q4","2012q4","2010q1", "2010q1","2010q1","2012q4", "2012q4","2012q4","2010q1", "2010q1","2010q1")),
.Names = c("name1","name2","year", "quarter", "time"),
row.names = c("1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12"), class =("data.frame"))
dt为什么使用$time
而不是$year
和$quarter
只需执行dplyr::安排(dt,name1,name2,年份,季度)
您尝试过的东西是如何不起作用的?我看到的唯一可能的区别是,您的季度现在是yearqtr
对象而不是字符串。如果您使用dt$time=format(dt$time,“%Y Q%Q”)
将它们恢复到“2012年第二季度”格式,这就是您想要的吗?
dt <- structure(list(
name1 = c("B","B","B","B","B","B", "C","C","C","C","C","C"),
name2 = c("A", "A", "D", "D", "E", "E","A", "A", "D", "D", "E", "E"),
year = c(2010,2012,2010,2012,2010,2012,2010,2012,2010,2012,2010,2012),
quarter = c(1,4,1,4,1,4,1,4,1,4,1,4),
time = c("2010q1","2012q4", "2010q1","2012q4","2010q1","2012q4","2010q1","2012q4","2010q1","2012q4","2010q1","2012q4")),
.Names = c("name1","name2","year", "quarter", "time"),
row.names = c("1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12"), class =("data.frame"))
dt$time <- as.yearqtr(dt$time)
dt <- dt[order(dt$name1, dt$name2, dt$time),]