根据r中的列值减去两个数据帧

我有两个数据帧：

f <- data.frame(
  CF = c(1,2,3,4,1,2,3,4), 
  Season = c("Fall", "Spring", "Summer", "Winter","Fall", "Spring", "Summer", "Winter"), 
  Tmax = c(51,65,83,38,52,68,90,45), 
  Tmin = c(30,40,53,19, 32,43,60,23))
h <- data.frame(
  Season = c("Fall", "Spring", "Summer", "Winter"), 
  Tmax = c(47,60,79,35), 
  Tmin = c(27,36,52,16)
)

---

我该怎么做？Dplyr解决方案始终受到赞赏。谢谢

这里有一个使用

dplyr

进行加法和减法的简单方法

库（dplyr）
f%>%
左联合（h，by=“seasure”）%>%
突变（Tmax_delta=Tmax.x-Tmax.y，
Tmin_delta=Tmin.x-Tmin.y）%>%
选择（CF，季节，以（“\u delta”）结束）

CF季节Tmax\u delta Tmin\u delta
1跌倒4 3
2弹簧5 4
3夏季4 1
4冬季3 3
5.1跌倒5.5
6 2弹簧8 7
7 3夏季11 8
8 4冬季10 7

使用

• 匹配

• 合并

---

看起来您实际上不需要这里的

dplyr

。您是否检查了

merge

功能？到目前为止，您尝试过哪些功能不起作用？这有助于

merge（f，h，by=c（'seasure'），all.x=t）

delta <- data.frame(
  CF = c(1,2,3,4,1,2,3,4), 
  Season = c("Fall", "Spring", "Summer", "Winter","Fall", "Spring", "Summer", "Winter"), 
  Tmax_delta = c(4,5,4,3,5,8,11,10), 
  Tmin_delta = c(3,4,1,3,5,7,8,7)
)

nms <- c("Tmax","Tmin")
delta <- cbind(f[1:2],setNames(f[nms]-h[match(f$Season,h$Season),][nms],paste0(nms,"_delta")))

> delta
  CF Season Tmax_delta Tmin_delta
1  1   Fall          4          3
2  2 Spring          5          4
3  3 Summer          4          1
4  4 Winter          3          3
5  1   Fall          5          5
6  2 Spring          8          7
7  3 Summer         11          8
8  4 Winter         10          7

u <- merge(f, h, by = "Season", all = TRUE)
d <- u[grep("\\.x", names(u))] - u[grep("\\.y", names(u))]
delta <- cbind(u[c("CF", "Season")], setNames(d, gsub("\\..*", "_delta", names(d))))

> delta
  CF Season Tmax_delta Tmin_delta
1  1   Fall          4          3
2  1   Fall          5          5
3  2 Spring          5          4
4  2 Spring          8          7
5  3 Summer          4          1
6  3 Summer         11          8
7  4 Winter          3          3
8  4 Winter         10          7