R 基于lappy的列表预测

我试图使用dplyr和lapply来估计一组模型。我估计一个概率回归，结果存储在一个列表中。然后我想使用predict函数来预测新数据集上的值。我的模型运行，但结果为零值。我做错了什么

# Code from the original question
library(dplyr)

year <- rep(2014:2015, length.out=10000)
group <- sample(c(0,1,2,3,4,5,6), replace=TRUE, size=10000)
value <- sample(10000, replace=T)
female <- sample(c(0,1), replace=TRUE, size=10000)
smoker <- sample(c(0,1), replace=TRUE, size=10000)
dta <- data.frame(year=year, group=group, value=value, female=female, smoker=smoker)

# cut the dataset into list
table_list <- dta %>%
  group_by(year, group) %>%
  group_split()

# fit model per subgroup
model_list <- lapply(table_list, function(x) glm(smoker ~ female, data=x,
                                                 family=binomial(link="probit")))

# create new dataset where female =1
dat_new <- data.frame(dta[, c("smoker", "year", "group")], female=1) 

# cut into list
pred_list <- dat_new %>%
  group_by(year, group) %>%
  group_split()

# do prediction
pred2 <- Map(function(x, y) predict.glm(x, type = "response", newdata = y), 
             model_list, pred_list)

#原始问题的代码
图书馆（dplyr）
年份您应该将
lappy
置于
model\u列表
之上

pred1 <- lapply(model_list, function(x) predict.glm(x, type = "response"))

pred2 <- Map(function(x, y) predict.glm(x, type = "response", newdata = y), 
          model_list, pred_list)