r中rbind对象到数据帧的问题

我创建了一个表：

RpgCharDF <- data.frame(Name = character(),
                        Level = integer(),
                        ClassChar = character(),
                        Race = character(),
                        HP = integer(),
                        Attack = integer(),
                        Resist = integer())

DF中有NA值

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我哪里做错了？那代码怎么了？我需要注意的是，元素Artur和Dawid都是正常创建的。当我在环境中单击时，两者都有一个填充的名称等。

使用rbindlist而不是rbind:

RpgCharDF <- data.frame(Name = character(),
                        Level = integer(),
                        rpgClass = character(),
                        Race = character(),
                        HP = integer(),
                        Attack = integer(),
                        Resist = integer())

RPGcharacter <- function(Name, Level, rpgClass, Race, HP, Attack, Resist){
  value <- list(Name= Name, Level = Level, rpgClass = rpgClass,Race=Race, HP = HP, Attack = Attack, Resist = Resist)
  attr(value, "class") <- "RPGcharacter"
  value
}

library(data.table)

Artur <- RPGcharacter("Artur", 22, "Warlock", "Dwarf", 130, 12, 3)
Dawid <- RPGcharacter("Dawid", 1, "Homeless", "Gnome", 20, 2, 1)

RpgCharDF <- rbindlist(list(RpgCharDF, Dawid, Artur), fill = T, use.names = T)
RpgCharDF

---

RpgCharDF使用rbindlist而不是rbind:

RpgCharDF <- data.frame(Name = character(),
                        Level = integer(),
                        rpgClass = character(),
                        Race = character(),
                        HP = integer(),
                        Attack = integer(),
                        Resist = integer())

RPGcharacter <- function(Name, Level, rpgClass, Race, HP, Attack, Resist){
  value <- list(Name= Name, Level = Level, rpgClass = rpgClass,Race=Race, HP = HP, Attack = Attack, Resist = Resist)
  attr(value, "class") <- "RPGcharacter"
  value
}

library(data.table)

Artur <- RPGcharacter("Artur", 22, "Warlock", "Dwarf", 130, 12, 3)
Dawid <- RPGcharacter("Dawid", 1, "Homeless", "Gnome", 20, 2, 1)

RpgCharDF <- rbindlist(list(RpgCharDF, Dawid, Artur), fill = T, use.names = T)
RpgCharDF

RpgCharDF当您调用
rbind
时，它将输出转换为
data.frame
。由于未指定字符串的处理方式，因此会将字符串转换为因子，因此，当您尝试添加第二行时，它会为字符列名称和攻击提供NA

您可以使用：

RpgCharDF <- rbind(RpgCharDF, Dawid, stringsAsFactors = FALSE)
RpgCharDF <- rbind(RpgCharDF, Artur, stringsAsFactors = FALSE)

RpgCharDF当您调用
rbind
时，它将输出转换为
data.frame
。由于未指定字符串的处理方式，因此会将字符串转换为因子，因此，当您尝试添加第二行时，它会为字符列名称和攻击提供NA

您可以使用：

RpgCharDF <- rbind(RpgCharDF, Dawid, stringsAsFactors = FALSE)
RpgCharDF <- rbind(RpgCharDF, Artur, stringsAsFactors = FALSE)

RpgCharDF您可以转换为
字符
类，并且应该是写得很好的问题。继续。你可以转换成
字符
类，并且应该是一个写得很好的问题。继续说下去。非常感谢你的解释！工作正常：）也许你知道为什么DF中的索引（行名）是2和21？不是1和2？嗯。。。这真的很奇怪。。。我不知道你为什么会得到这些行名，对不起。非常感谢你的解释！工作正常：）也许你知道为什么DF中的索引（行名）是2和21？不是1和2？嗯。。。这真的很奇怪。。。对不起，我不知道你为什么会得到这些行名。
    NAME  Level RPGClass   HP  ATTACK  RESIST
1   Dawid   1   Homeless    20    2      1
2   NA      22  NA         130   12      3

RpgCharDF <- data.frame(Name = character(),
                        Level = integer(),
                        rpgClass = character(),
                        Race = character(),
                        HP = integer(),
                        Attack = integer(),
                        Resist = integer())

RPGcharacter <- function(Name, Level, rpgClass, Race, HP, Attack, Resist){
  value <- list(Name= Name, Level = Level, rpgClass = rpgClass,Race=Race, HP = HP, Attack = Attack, Resist = Resist)
  attr(value, "class") <- "RPGcharacter"
  value
}

library(data.table)

Artur <- RPGcharacter("Artur", 22, "Warlock", "Dwarf", 130, 12, 3)
Dawid <- RPGcharacter("Dawid", 1, "Homeless", "Gnome", 20, 2, 1)

RpgCharDF <- rbindlist(list(RpgCharDF, Dawid, Artur), fill = T, use.names = T)
RpgCharDF

RpgCharDF <- rbind(RpgCharDF, Dawid, stringsAsFactors = FALSE)
RpgCharDF <- rbind(RpgCharDF, Artur, stringsAsFactors = FALSE)

RpgCharDF <- do.call(rbind, list(RpgCharDF, Dawid, Artur))