R 如何在热图中建立因式分解的颜色梯度_R_Ggplot2_Colors_Heatmap

R 如何在热图中建立因式分解的颜色梯度

r colors

R 如何在热图中建立因式分解的颜色梯度,r,ggplot2,colors,heatmap,R,Ggplot2,Colors,Heatmap,我用R中的ggplot2生成了这个图。生成绘图的代码如下所示： ggplot(mockdata) + facet_grid(~ type, scales='free_x', space="free_x") + geom_tile(aes(variable, Measurement, fill = mockdata$plotval), colour = "dark red") + scale_fill_gradient2(limits=c(-20, 20),high = "f

我用R中的ggplot2生成了这个图。

生成绘图的代码如下所示：

ggplot(mockdata) + 
  facet_grid(~ type, scales='free_x', space="free_x") +
  geom_tile(aes(variable, Measurement, fill = mockdata$plotval), colour = "dark red")  + 
  scale_fill_gradient2(limits=c(-20, 20),high = "firebrick3", low = "dodgerblue4") + 
  theme_minimal() + 
  theme(axis.text.x=element_text(size=28, angle=90), axis.text.y=element_text(size=28)) + 
  labs(title="", x="", y="", fill="")

从绘图和代码中可以明显看出，配色方案的范围为-20到20。我的数据中的plotval实际上代表P值的-log10，因此总是一个正数，但我将其拆分为正数和负数，方法是将其乘以1或-1，具体取决于效果的方向（mockdata中的方向列）

我想做的是将我的渐变色条一分为二，使其范围仅为0到20，但我仍然希望每个瓷砖是红色或蓝色，我希望蓝色和红色的强度可以在颜色条上并排看到。我还想增加颜色条的大小，但我想这完全是另一个问题

dput(mockdata)
structure(list(Measurement = structure(c(20L, 19L, 18L, 17L, 
16L, 15L, 14L, 13L, 12L, 11L, 10L, 9L, 8L, 7L, 6L, 5L, 4L, 3L, 
2L, 1L, 20L, 19L, 18L, 17L, 16L, 15L, 14L, 13L, 12L, 11L, 10L, 
9L, 8L, 7L, 6L, 5L, 4L, 3L, 2L, 1L, 20L, 19L, 18L, 17L, 16L, 
15L, 14L, 13L, 12L, 11L, 10L, 9L, 8L, 7L, 6L, 5L, 4L, 3L, 2L, 
1L, 20L, 19L, 18L, 17L, 16L, 15L, 14L, 13L, 12L, 11L, 10L, 9L, 
8L, 7L, 6L, 5L, 4L, 3L, 2L, 1L, 20L, 19L, 18L, 17L, 16L, 15L, 
14L, 13L, 12L, 11L, 10L, 9L, 8L, 7L, 6L, 5L, 4L, 3L, 2L, 1L, 
20L, 19L, 18L, 17L, 16L, 15L, 14L, 13L, 12L, 11L, 10L, 9L, 8L, 
7L, 6L, 5L, 4L, 3L, 2L, 1L, 20L, 19L, 18L, 17L, 16L, 15L, 14L, 
13L, 12L, 11L, 10L, 9L, 8L, 7L, 6L, 5L, 4L, 3L, 2L, 1L, 20L, 
19L, 18L, 17L, 16L, 15L, 14L, 13L, 12L, 11L, 10L, 9L, 8L, 7L, 
6L, 5L, 4L, 3L, 2L, 1L, 20L, 19L, 18L, 17L, 16L, 15L, 14L, 13L, 
12L, 11L, 10L, 9L, 8L, 7L, 6L, 5L, 4L, 3L, 2L, 1L), .Label = c("1", 
"2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", 
"14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", 
"25", "26", "27", "28", "29", "30", "31", "32", "33", "34", "35", 
"36", "37", "38", "39", "40", "41", "42"), class = "factor"), 
    category = structure(c(3L, 4L, 4L, 4L, 5L, 5L, 6L, 6L, 6L, 
    6L, 6L, 6L, 6L, 7L, 7L, 7L, 7L, 7L, 7L, 8L, 3L, 4L, 4L, 4L, 
    5L, 5L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 7L, 7L, 7L, 7L, 7L, 7L, 
    8L, 3L, 4L, 4L, 4L, 5L, 5L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 7L, 
    7L, 7L, 7L, 7L, 7L, 8L, 3L, 4L, 4L, 4L, 5L, 5L, 6L, 6L, 6L, 
    6L, 6L, 6L, 6L, 7L, 7L, 7L, 7L, 7L, 7L, 8L, 3L, 4L, 4L, 4L, 
    5L, 5L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 7L, 7L, 7L, 7L, 7L, 7L, 
    8L, 3L, 4L, 4L, 4L, 5L, 5L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 7L, 
    7L, 7L, 7L, 7L, 7L, 8L, 3L, 4L, 4L, 4L, 5L, 5L, 6L, 6L, 6L, 
    6L, 6L, 6L, 6L, 7L, 7L, 7L, 7L, 7L, 7L, 8L, 3L, 4L, 4L, 4L, 
    5L, 5L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 7L, 7L, 7L, 7L, 7L, 7L, 
    8L, 3L, 4L, 4L, 4L, 5L, 5L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 7L, 
    7L, 7L, 7L, 7L, 7L, 8L), .Label = c("x1", "x2", "x3", "x4", 
    "x5", "x6", "x7", "x8", "x9"), class = "factor"), variable = structure(c(1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 
    2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 3L, 3L, 
    3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 4L, 
    4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 
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    "B", "C", "a", "b", "c", "d", "e", "f"), class = "factor"), 
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非常感谢您的帮助

您能澄清一下：哪个变量分割颜色条吗？

方向的每个值是否应该有一个？另外，您需要两个色标，每个色标都基于limits=c（0,20）
-但plotval
的某些值为负值，因此它们不会显示。这就是你的意思吗？对不起，你描述的不是我的意思。瓷砖的颜色应由效果的方向决定。这可以通过将颜色与mockdata的方向变量链接来实现，也可以通过让颜色由plotval的符号确定来实现。在第一种情况下，可以对plotval变量进行重新编码，使其仅包含正值，因此可以基于limits=c（0,20）
的比例。进一步澄清：应显示plotval
的所有值。abs（plotval）
的值应确定强度，而符号应确定颜色在您发布的数据中，plotval
通常为负值，但您的问题是它应始终为正值。起初我认为可能plotval
是通过乘以direction
创建的，但是plotval
可以是负数，即使direction
是正数，反之亦然。