R 表列表的xtable输出

我有一个表列表，希望保存它以用于LaTex输出。代码如下：

Data <- esoph[ , 1:3]
library(plyr)
combos <- combn(ncol(Data),2)

TabelFn <- function(x) {
  Table <- addmargins(table(Data[, x[1]], Data[, x[2]]))
  return(Table)
  }

Table <- alply(.data=combos, .margins=2, .fun=TabelFn, .expand=TRUE)
library(xtable)

---

要发送三个列联表的输出，我必须编写三个这样的命令。在这种情况下是可行的。但对于我的实际数据，我有很多列联表。我想知道如何更有效地发送所有应急表格。一种选择是只打印列表

表

，而不打印

xtable

。但我希望列联表具有良好的输出格式。感谢您的时间和帮助。

鉴于缺乏实际数据及其结构，这里有一种方法

TabelFn2 <- function(x) {
  Table <- addmargins(table(Data[, x[1]], Data[, x[2]]))
  print(xtable(Table$'1', caption = "Contingency table for agegp and alcgp", 
       label = "tab:Table", digits = c(0, rep(0, ncol(Table$'1'))),
       align = paste(paste("l|", paste(rep("r", ncol(Table$'1')-1), 
       collapse = ''), sep = ""), "l", sep = "")),
      table.placement = "tbp", caption.placement = "top",
      hline.after = c(-1, 0, nrow(Table$'1')))
 }

<<echo = F, results = tex>>=
a_ply(.data=combos, .margins=2, .fun=TabelFn2)
@

---

TabelFn2我需要一些模拟数据来处理

Data <- data.frame(a=rbinom(100,1,0.5), b=rbinom(100,1,0.3), c=rbinom(100,1,0.6))

您可以通过迭代
Table
的索引而不是
Table
本身来获得正确的标签

a_ply(seq_along(Table), 1, function(i) {
  print(xtable(Table[[i]], 
      caption = "Contingency table for agegp and alcgp", #This information is not in the Table[[i]] anywhere
      label = paste("tab:Table[",i,"]",sep=""), 
      digits = c(0, rep(0, ncol(Table[[i]]))),
    align = paste(paste("l|", paste(rep("r", ncol(Table[[i]])-1), collapse = ''), sep = ""), "l", sep = "")),
    table.placement = "tbp",
    caption.placement = "top",
    hline.after = c(-1, 0, nrow(Table[[i]])))       
})

由于信息不存在，无法自动制作标题。但是，如果修改
表fn
函数，则可以添加该信息，然后将其提取出来

TabelFn <- function(x) {
  Table <- addmargins(table(Data[, x[1]], Data[, x[2]]))
  names(attr(Table,"dimnames")) <- names(Data)[x]
  return(Table)
}

Table <- alply(.data=combos, .margins=2, .fun=TabelFn, .expand=TRUE)

a_ply(seq_along(Table), 1, function(i) {
  vars <- names(attr(Table[[i]],"dimnames"))
  print(xtable(Table[[i]], 
      caption = paste("Contingency table for", vars[1], "and", vars[2]),
      label = paste("tab:Table[",i,"]",sep=""), # This is also problematic
      digits = c(0, rep(0, ncol(Table[[i]]))),
    align = paste(paste("l|", paste(rep("r", ncol(Table[[i]])-1), collapse = ''), sep = ""), "l", sep = "")),
    table.placement = "tbp",
    caption.placement = "top",
    hline.after = c(-1, 0, nrow(Table[[i]])))       
})

TabelFn@Ramnath，谢谢你的回复。使用给定的代码Rnw文件可以工作，但使用LaTex时，我收到了以下错误消息：LaTex错误：未处理的浮点太多。甚至我也使用了\usepackage[section]{placeins}。任何评论。再次感谢。@Brian Diggs，非常感谢。你总是来救我。再次感谢。@Brian Diggs，如果您能以同样的方式帮助我获得频率，我将不胜感激。我使用这个命令Freq，变量很少，效果很好。但根据我的实际数据，我得到了一个错误：太多未经处理的絮状物。@MYaseen208:对于频率，我会稍微改变一下
Freq关于太多未处理的浮点，可以尝试将
table.placement
更改为
H
，并将
\usepackage{float}
添加到swave文件的前导。我不知道它是否会起作用，但它可能会起作用。
a_ply(seq_along(Table), 1, function(i) {
  print(xtable(Table[[i]], 
      caption = "Contingency table for agegp and alcgp", #This information is not in the Table[[i]] anywhere
      label = paste("tab:Table[",i,"]",sep=""), 
      digits = c(0, rep(0, ncol(Table[[i]]))),
    align = paste(paste("l|", paste(rep("r", ncol(Table[[i]])-1), collapse = ''), sep = ""), "l", sep = "")),
    table.placement = "tbp",
    caption.placement = "top",
    hline.after = c(-1, 0, nrow(Table[[i]])))       
})

TabelFn <- function(x) {
  Table <- addmargins(table(Data[, x[1]], Data[, x[2]]))
  names(attr(Table,"dimnames")) <- names(Data)[x]
  return(Table)
}

Table <- alply(.data=combos, .margins=2, .fun=TabelFn, .expand=TRUE)

a_ply(seq_along(Table), 1, function(i) {
  vars <- names(attr(Table[[i]],"dimnames"))
  print(xtable(Table[[i]], 
      caption = paste("Contingency table for", vars[1], "and", vars[2]),
      label = paste("tab:Table[",i,"]",sep=""), # This is also problematic
      digits = c(0, rep(0, ncol(Table[[i]]))),
    align = paste(paste("l|", paste(rep("r", ncol(Table[[i]])-1), collapse = ''), sep = ""), "l", sep = "")),
    table.placement = "tbp",
    caption.placement = "top",
    hline.after = c(-1, 0, nrow(Table[[i]])))       
})