R 将字符串拆分为行和列
我有一根长长的绳子:R 将字符串拆分为行和列,r,string,mutate,R,String,Mutate,我有一根长长的绳子: mystr <- "foo one undefined + foo two undefined + BAR three undefined + " 使用+创建新行,然后使用空格创建列。这可能吗?我尝试使用str_split和mutate,但我似乎不知道如何创建新行。感谢您的帮助 在base R中使用gsub将+替换为\n后,我们可以使用read.table read.table(text = gsub("+", "\n", mystr, fi
mystr <- "foo one undefined + foo two undefined + BAR three undefined + "
使用
+
创建新行,然后使用空格创建列。这可能吗?我尝试使用str_split和mutate,但我似乎不知道如何创建新行。感谢您的帮助 在base R
中使用gsub
将+
替换为\n
后,我们可以使用read.table
read.table(text = gsub("+", "\n", mystr, fixed = TRUE),
header = FALSE, col.names = paste0('x', 1:3))
# x1 x2 x3
#1 foo one undefined
#2 foo two undefined
#3 BAR three undefined
或者使用strsplit
和read.table
read.table(text = strsplit(mystr, " + ", fixed = TRUE)[[1]], header = FALSE)
或者我们可以使用
fread
library(data.table)
fread(text = gsub("+", "\n", mystr, fixed = TRUE), header = FALSE)
或者使用
tidyverse
library(dplyr)
library(tidyr)
tibble(col1 = mystr) %>%
separate_rows(col1, sep="\\s*\\+\\s*") %>%
separate(col1, into = c('x1', 'x2', 'x3')) %>%
na.omit
# A tibble: 3 x 3
# x1 x2 x3
# <chr> <chr> <chr>
#1 foo one undefined
#2 foo two undefined
#3 BAR three undefined
库(dplyr)
图书馆(tidyr)
TIBLE(col1=mystr)%>%
单独的\u行(col1,sep=“\\s*\\+\\s*”)%>%
分离(col1,分为=c('x1','x2','x3'))%>%
省略
#一个tibble:3x3
#x1x2x3
#
#1个foo一个未定义
#2 foo 2未定义
#3条3未定义
另一个基本R解决方案:
data.frame(do.call("rbind", sapply(strsplit(trimws(mystr, "both"), "\\+"),
function(x){strsplit(trimws(x, "both"), "\\s+")})))
data.frame(do.call("rbind", sapply(strsplit(trimws(mystr, "both"), "\\+"),
function(x){strsplit(trimws(x, "both"), "\\s+")})))