R 有没有办法缩短一系列的类
目前,我正在读取如下数据文件:R 有没有办法缩短一系列的类,r,R,目前,我正在读取如下数据文件: setwd("N:/HH Scallop Growth Project/Ring data by cruise/") growth <- read.csv("Growth.csv",sep=",",header=TRUE, colClasses=c("character","character","character","numeric", "char
setwd("N:/HH Scallop Growth Project/Ring data by cruise/")
growth <- read.csv("Growth.csv",sep=",",header=TRUE,
colClasses=c("character","character","character","numeric",
"character","numeric","numeric","numeric",
"numeric","numeric","numeric","numeric",
"numeric","numeric","character","numeric",
"character","numeric","numeric","numeric",
"numeric","character","numeric","numeric",
"numeric"))
setwd(“N:/HH扇贝生长项目/cruise提供的环数据/”)
增长关于rep
功能:
R> rep(1:3, 2:4)
[1] 1 1 2 2 2 3 3 3 3
大概是
cc = rep(c("character", "numeric"), c(2, 4))
read.csv("Growth.csv", header=TRUE, colClasses=cc)
可以使用长度和值构造列表
xList <- list(lengths = c(3,1,1,9,1,1,1,4,1,3)
, values = rep(c("character", "numeric"), 5))
尝试创建一个25个向量,其条目都是的“数值”
,然后用的“字符”
替换其中的少数。还要注意,header=TRUE
和sep=“,”
是read.csv
的默认值,因此可以忽略它们
colClasses <- replace(rep("numeric", 25), c(1:3, 5, 15, 17, 22), "character")
growth <- read.csv("Growth.csv", colClasses = colClasses)
colClasses如果不显式指定colClasses
,并且只使用stringsAsFactors=FALSE
,该怎么办?这是否会导致错误的colClasses
?
colClasses <- replace(rep("numeric", 25), c(1:3, 5, 15, 17, 22), "character")
growth <- read.csv("Growth.csv", colClasses = colClasses)