R 基于模式将data.table列拆分为许多未知数量的列

我想将

数据的
B列
拆分。表

dt1

根据其值之间的空间将其拆分为许多列

df1 <- 
  structure(list(B = c("3,845,168 15,467,645 15,054,813 913 30,523,371", 
        "3,104,154 12,495,278 12,298,236 223 24,793,737", "741,014 2,972,367 2,756,577 690 5,729,634", 
        "218,044 1,035,308 1,008,748 18 2,044,074", "200,744 961,775 942,901 13 1,904,689", 
        "17,300 73,533 65,847 5 139,385"), C = c("17,743,645", "14,456,435", 
        "3,287,210", "1,165,692", "1,071,138", "94,554"), D = c("102.74", 
        "101.60", "107.83", "102.63", "102.00", "111.67"), E = c("2.89", 
        "2.87", "2.96", "2.99", "3.07", "2.06")), .Names = c("B", "C", 
        "D", "E"), row.names = c(NA, -6L), class = "data.frame"
        )
library(data.table)
dt1 <- data.table(df1)
dt1
                                                B          C      D    E
1: 3,845,168 15,467,645 15,054,813 913 30,523,371 17,743,645 102.74 2.89
2: 3,104,154 12,495,278 12,298,236 223 24,793,737 14,456,435 101.60 2.87
3:      741,014 2,972,367 2,756,577 690 5,729,634  3,287,210 107.83 2.96
4:       218,044 1,035,308 1,008,748 18 2,044,074  1,165,692 102.63 2.99
5:           200,744 961,775 942,901 13 1,904,689  1,071,138 102.00 3.07
6:                 17,300 73,533 65,847 5 139,385     94,554 111.67 2.06

---

df1我们可以使用
tstrsplit

tmp <- dt1[, tstrsplit(B, "\\s+")]
dt1[, paste0("B", seq_along(tmp)) := tmp]
rm(tmp)

dt1[, paste0("B", seq_len(M)) := tstrsplit(gsub(",", "", B), " ",
         fixed = TRUE, type.convert = TRUE)]

更新
由于
，
不在
数值列中考虑，我们将其删除，并在
tstrsplit

tmp <- dt1[, tstrsplit(B, "\\s+")]
dt1[, paste0("B", seq_along(tmp)) := tmp]
rm(tmp)

dt1[, paste0("B", seq_len(M)) := tstrsplit(gsub(",", "", B), " ",
         fixed = TRUE, type.convert = TRUE)]

感谢@akrun提供了很好的解决方案。如果您能指导如何转换
B1，…，将不胜感激，B5
转换为数值向量。Thanks@MYaseen208更新了帖子谢谢。还需要将列转换为包含
的数字。任何想法。@MYaseen208在执行拆分之前，您可以使用
dt1[，（名称（dt1））：=lapply（.SD，函数（x）type.convert（as.character（x），as.is=TRUE））
]