使用dplyr按组按最低和最高年份过滤_R_Filter_Dplyr

使用dplyr按组按最低和最高年份过滤

r filter

使用dplyr按组按最低和最高年份过滤,r,filter,dplyr,R,Filter,Dplyr,我觉得这里的答案很明显，但我无法确定。我有这个数据框： df <- structure(list(SIC = c(3L, 12L, 11L, 7L, 18L, 5L, 19L, 17L, 1L, 10L, 8L, 16L, 14L, 2L, 15L, 6L, 9L, 4L, 13L, 3L, 12L, 11L, 7L, 18L, 5L, 19L, 17L, 1L, 10L, 8L, 16L, 14L, 2L, 15L, 6L, 9L, 4L, 13L, 3L, 12L, 11L, 7

我觉得这里的答案很明显，但我无法确定。我有这个数据框：

df <- structure(list(SIC = c(3L, 12L, 11L, 7L, 18L, 5L, 19L, 17L, 1L, 
10L, 8L, 16L, 14L, 2L, 15L, 6L, 9L, 4L, 13L, 3L, 12L, 11L, 7L, 
18L, 5L, 19L, 17L, 1L, 10L, 8L, 16L, 14L, 2L, 15L, 6L, 9L, 4L, 
13L, 3L, 12L, 11L, 7L, 18L, 5L, 19L, 17L, 1L, 10L, 8L, 16L, 14L, 
2L, 15L, 6L, 9L, 4L, 13L, 3L, 12L, 11L, 7L, 18L, 5L, 19L, 17L, 
1L, 10L, 8L, 16L, 14L, 2L, 15L, 6L, 9L, 4L, 13L, 3L, 12L, 11L, 
7L, 18L, 5L, 19L, 17L, 1L, 10L, 8L, 16L, 14L, 2L, 15L, 6L, 9L, 
4L, 13L, 3L, 12L, 11L, 7L, 18L, 5L, 19L, 17L, 1L, 10L, 8L, 16L, 
14L, 2L, 15L, 6L, 9L, 4L, 13L, 3L, 12L, 11L, 7L, 18L, 5L, 19L, 
17L, 1L, 10L, 8L, 16L, 14L, 2L, 15L, 6L, 9L, 4L, 13L, 3L, 12L, 
11L, 7L, 18L, 5L, 19L, 17L, 1L, 10L, 8L, 16L, 14L, 2L, 15L, 6L, 
9L, 4L, 13L), year = c(2011, 2011, 2011, 2011, 2011, 2011, 2011, 
2011, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 2011, 
2011, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 
2012, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2012, 2013, 2013, 
2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 
2013, 2013, 2013, 2013, 2013, 2013, 2014, 2014, 2014, 2014, 2014, 
2014, 2014, 2014, 2014, 2014, 2014, 2014, 2014, 2014, 2014, 2014, 
2014, 2014, 2014, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 
2015, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 2015, 
2016, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 
2016, 2016, 2016, 2016, 2016, 2016, 2016, 2016, 2017, 2017, 2017, 
2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 
2017, 2017, 2017, 2017, 2017, 2018, 2018, 2018, 2018, 2018, 2018, 
2018, 2018, 2018, 2018, 2018, 2018, 2018, 2018, 2018, 2018, 2018, 
2018, 2018), value = c(NA, 0.081, 0.218, 0.212, NA, 0.092, 0.142, 
0.001, 0.045, 0.143, 0.361, 0.175, 0.295, 0.003, 0.146, 0.01, 
0.163, NA, 0.225, NA, 0.108, 0.274, 0.219, NA, 0.097, 0.148, 
-0.049, 0.098, 0.26, 0.251, 0.153, 0.262, 0.119, 0.096, 0, 0.149, 
NA, NA, NA, 0.064, 0.27, 0.16, NA, 0.103, 0.148, -0.029, 0.084, 
0.219, 0.314, 0.142, 0.255, 0.026, 0.031, -0.003, 0.164, NA, 
NA, NA, NA, 0.257394804, 0.124025397, NA, 0.071727544, 0.13439, 
-0.017419321, 0.091993981, 0.171021874, 0.308369685, 0.208573024, 
0.310316421, 0.06216349, 0.074913633, -0.034273066, 0.181129287, 
0.07876301, 0.121, NA, -0.063226494, 0.233968039, 0.179367136, 
NA, 0.105362761, 0.15319907, -0.033967241, -0.035027867, 0.144316565, 
0.304955404, 0.069662044, 0.304262651, 0.075256422, 0.051273353, 
-0.067541918, 0.157814304, 0.050231459, 0.06308377, NA, -8.4, 
21, 17.9, NA, 7.3, 12.6, -1.2, 4.1, 10.3, 30.2, 8.7, 28.1, 4.7, 
1.3, -7.7, 12.5, 15.9, 19.4, 16.9, 4, 18.2, 13.5, NA, 10.9, 12.8, 
-0.7, 4.2, 7.5, 26.8, 5, 30.3, 0.9, 2.5, -2.4, 13.5, 12.8, 17, 
NA, NA, 17.2, 17.7, NA, 0.6, 11.6, -2.9, 3, 18.7, 31, 6.2, 30.1, 
-1.1, 5.7, -0.5, 13.6, 6.1, -7)), class = c("tbl_df", "tbl", 
"data.frame"), row.names = c(NA, -152L))

有什么想法吗？谢谢

编辑：

数据的一个简单版本是这样过滤：

tibble(
  SIC = c(1,1,1,2,2, 2), 
  year = c(2011, 2012, 2013, 2011, 2012, 2013), 
  value = c(3, 4, NA, NA, 4, NA)
) %>% 
  filter(!is.na(value)) 

# A tibble: 3 x 3
    SIC  year value
  <dbl> <dbl> <dbl>
1     1  2011     3
2     1  2012     4
3     2  2012     4

所有出现一次的行应同时计为最小值和最大值。有没有办法为应用过滤器后只出现一次的行创建一个重复行？

我的理解是，您希望SIC有两行，其最大年份和最小年份相同。我想你可以把这两行分开绑起来，这样它仍然有两行

library(dplyr)

min_year <- df %>% 
  group_by(SIC) %>% 
  filter(!is.na(value)) %>% 
  filter(year %in% c(min(year)))

max_year <-  df %>% 
  group_by(SIC) %>% 
  filter(!is.na(value)) %>% 
  filter(year %in% c(max(year)))

total <- min_year %>% rbind(max_year)

我的理解是，您希望SIC有两行，其最大年份和最小年份相同。我想你可以把这两行分开绑起来，这样它仍然有两行

library(dplyr)

min_year <- df %>% 
  group_by(SIC) %>% 
  filter(!is.na(value)) %>% 
  filter(year %in% c(min(year)))

max_year <-  df %>% 
  group_by(SIC) %>% 
  filter(!is.na(value)) %>% 
  filter(year %in% c(max(year)))

total <- min_year %>% rbind(max_year)

尝试使用slice：

输出：

# A tibble: 4 x 3
# Groups:   SIC [2]
    SIC  year value
  <dbl> <dbl> <dbl>
1     1  2011     3
2     1  2012     4
3     2  2012     4
4     2  2012     4

i、 e.它重复年份，而过滤器只保留与参数对应的内容：

# A tibble: 35 x 3
# Groups:   SIC [18]
     SIC  year    value
   <int> <dbl>    <dbl>
 1     1  2011   0.045 
 2     1  2018   3     
 3     2  2011   0.003 
 4     2  2018  -1.1   
 5     3  2017  16.9   
 6     4  2014   0.0788

我正在使用dplyr 0.8。

尝试使用slice：

输出：

# A tibble: 4 x 3
# Groups:   SIC [2]
    SIC  year value
  <dbl> <dbl> <dbl>
1     1  2011     3
2     1  2012     4
3     2  2012     4
4     2  2012     4

i、 e.它重复年份，而过滤器只保留与参数对应的内容：

# A tibble: 35 x 3
# Groups:   SIC [18]
     SIC  year    value
   <int> <dbl>    <dbl>
 1     1  2011   0.045 
 2     1  2018   3     
 3     2  2011   0.003 
 4     2  2018  -1.1   
 5     3  2017  16.9   
 6     4  2014   0.0788

我正在使用dplyr 0.8。

我认为这就是您希望实现的目标。希望有帮助：

#Create two tibbles (MAX & MIN)
max.vals<-df %>%
  group_by(year) %>%
  slice(which.max(value))

min.vals<-df %>%
  group_by(year) %>%
  slice(which.min(value))

#Create new DF, with MAX & MIN for each (unique) year:
clean.df<-data.frame(SIC=max.vals$SIC,
             year = max.vals$year,
             max.value = max.vals$value,
             min.value = min.vals$value,stringsAsFactors = FALSE)

> head(clean.df)
  SIC year  max.value   min.value
1   8 2011  0.3610000  0.00100000
2  11 2012  0.2740000 -0.04900000
3   8 2013  0.3140000 -0.02900000
4  14 2014  0.3103164 -0.03427307
5   8 2015  0.3049554 -0.06754192
6   8 2016 30.2000000 -8.40000000

编辑我是一个可怕的人，我只是看到你想要它的SIC。别担心，希望这就是你需要的：

SIC.low<-df %>%
  group_by(SIC) %>%
  slice(which.min(value))

SIC.high<-df %>%
  group_by(SIC) %>%
  slice(which.max(value))

clean.df2<-data.frame(SIC=SIC.high$SIC,
                     year.high = SIC.high$year,
                     max.value = SIC.high$value,
                     year.low= SIC.low$year,
                     min.value = SIC.low$value,stringsAsFactors = FALSE)


> head(clean.df2)
  SIC year.high max.value year.low   min.value
1   1      2017      4.20     2015 -0.03502787
2   2      2016      4.70     2018 -1.10000000
3   3      2017     16.90     2017 16.90000000
4   4      2016     15.90     2015  0.05023146
5   5      2017     10.90     2014  0.07172754
6   6      2011      0.01     2016 -7.70000000

我认为这就是你希望实现的目标。希望有帮助：

#Create two tibbles (MAX & MIN)
max.vals<-df %>%
  group_by(year) %>%
  slice(which.max(value))

min.vals<-df %>%
  group_by(year) %>%
  slice(which.min(value))

#Create new DF, with MAX & MIN for each (unique) year:
clean.df<-data.frame(SIC=max.vals$SIC,
             year = max.vals$year,
             max.value = max.vals$value,
             min.value = min.vals$value,stringsAsFactors = FALSE)

> head(clean.df)
  SIC year  max.value   min.value
1   8 2011  0.3610000  0.00100000
2  11 2012  0.2740000 -0.04900000
3   8 2013  0.3140000 -0.02900000
4  14 2014  0.3103164 -0.03427307
5   8 2015  0.3049554 -0.06754192
6   8 2016 30.2000000 -8.40000000

编辑我是一个可怕的人，我只是看到你想要它的SIC。别担心，希望这就是你需要的：

SIC.low<-df %>%
  group_by(SIC) %>%
  slice(which.min(value))

SIC.high<-df %>%
  group_by(SIC) %>%
  slice(which.max(value))

clean.df2<-data.frame(SIC=SIC.high$SIC,
                     year.high = SIC.high$year,
                     max.value = SIC.high$value,
                     year.low= SIC.low$year,
                     min.value = SIC.low$value,stringsAsFactors = FALSE)


> head(clean.df2)
  SIC year.high max.value year.low   min.value
1   1      2017      4.20     2015 -0.03502787
2   2      2016      4.70     2018 -1.10000000
3   3      2017     16.90     2017 16.90000000
4   4      2016     15.90     2015  0.05023146
5   5      2017     10.90     2014  0.07172754
6   6      2011      0.01     2016 -7.70000000

你能发布你的预期输出吗？@arg0naut，请看我的编辑。@elliot请看下面，我认为slice应该这样做，因为它会自动重复行。你能发布你的预期输出吗？@arg0naut，请看我的编辑。@elliot请看下面，我认为slice应该这样做，因为它会自动重复行。谢谢这项工作。注意，我确实需要更新我的dplyr，以便在slice中使用两个变量。不客气，谢谢你让我知道，我认为它在0.8之前就已经存在了-我已经更新了我的帖子。谢谢你的帮助。注意，我确实需要更新我的dplyr以在slice中使用两个变量。不客气，谢谢你让我知道，我认为它在0.8之前就已经存在了-我已经更新了我的帖子。