从expss R包在etable中添加行

从expss R包在etable中添加行,r,tidyverse,expss,R,Tidyverse,Expss,我想将特定位置的行添加到expssoutputetable。我使用了一些蛮力方法,总是在etable的开头添加行。在特定位置添加行的任何方法 library(tidyverse) library(expss) test1 <- mtcars %>% tab_cells(cyl) %>% tab_cols(vs) %>% tab_stat_cpct() %>% tab_pivot() test1 %>%

我想将特定位置的行添加到
expss
output
etable
。我使用了一些蛮力方法,总是在
etable
的开头添加行。在特定位置添加行的任何方法

library(tidyverse)
library(expss)

test1 <-
    mtcars %>% 
    tab_cells(cyl) %>% 
    tab_cols(vs) %>% 
    tab_stat_cpct() %>% 
    tab_pivot()

test1 %>% 
  tibble() %>% 
  tibble::add_row(.data = tibble("", test1[2, -1]/test1[1, -1]*100) %>% 
            set_names(names(test1))
          , .before = 3)
库(tidyverse)
图书馆(expss)
测试1%
tab_单元格(气缸)%>%
表列(vs)%>%
tab_stat_cpct()%>%
tab_pivot()
测试1%>%
tibble()%>%
tibble::添加_行(.data=tibble(“,test1[2,-1]/test1[1,-1]*100)%
设置名称(名称(test1))
,.before=3)

不确定是否有使用
expss
导出的简单方法,但我们可以使用
expss::add_rows()
和一个简单的自定义函数拆分表来完成此操作


insert_row基于@calwellst代码但具有自动比率计算的解决方案:

insert_ratio <- function(tbl, where) {
    if(is.character(where)) {
        # if where is character we search it in the rowlabels
        where = grep(where, tbl[[1]], fixed = TRUE)[1]
    }
    isTRUE(where>1) || stop("'where' should be greater than 1 for ratio calculation.")
    isTRUE(where<=NROW(tbl)) || stop("'where' should be less or equal than number of rows in the table.")
    tbl1 <- tbl[1:where,]
    to_insert = c(row_labels = tbl[[1]][where], tbl[where, -1]/tbl[where - 1, -1]*100)
    tbl2 <- tbl[(where+1):nrow(tbl),]
    tbl1 %>%
        add_rows(to_insert) %>%
        add_rows(tbl2)
}

insert_ratio(test1, 2)
 # |     |              |    vs |      |
 # |     |              |     0 |    1 |
 # | --- | ------------ | ----- | ---- |
 # | cyl |            4 |   5.6 | 71.4 |
 # |     |            6 |  16.7 | 28.6 |
 # |     |              | 300.0 | 40.0 |
 # |     |            8 |  77.8 |      |
 # |     | #Total cases |  18.0 | 14.0 |

insert_ratio(test1, "cyl|6")
 # the same result
insert_ratio 1)| | stop(“'where'对于比率计算应该大于1”)
isTRUE(其中1)| | stop(“'where'对于比率计算应大于1”)

isTRUE(感谢您提供了一个很好的解决方法。想知道如何使用
test1[2,-1]/test1[1,-1]*100
而不是输入
300,40
。太好了!我们可以在函数之外进行计算吗?
ratio = function(tbl, where, label = NULL){
    if(is.character(where)) {
        # if where is character we search it in the rowlabels
        where = grep(where, tbl[[1]], fixed = TRUE)[1]
    }
    isTRUE(where>1) || stop("'where' should be greater than 1 for ratio calculation.")
    isTRUE(where<=NROW(tbl)) || stop("'where' should be less or equal than number of rows in the table.")
    
    if(is.null(label)) label = tbl[[1]][where]
    c(row_labels = label, tbl[where, -1]/tbl[where - 1, -1]*100)
}

insert_row = function(tbl, where, row) {
    if(is.character(where)) {
        # if where is character we search it in the rowlabels
        where = grep(where, tbl[[1]], fixed = TRUE)[1]
    }
    isTRUE(where<=NROW(tbl)) || stop("'where' should be less or equal than number of rows in the table.")
    first_part = seq_len(where)
    tbl1 <- tbl[first_part,]
    
    tbl2 <- tbl[-first_part,]
    tbl1 %>%
        add_rows(row) %>%
        add_rows(tbl2)
}

insert_row(test1, 2, ratio(test1, 2))
insert_row(test1, "cyl|6", ratio(test1, "cyl|6"))