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React native 反应本机后嵌套表单数据_React Native - Fatal编程技术网

React native 反应本机后嵌套表单数据

React native 反应本机后嵌套表单数据,react-native,React Native,我正在尝试使用formdata发布嵌套值。我是这样尝试的: const {phone} = this.state let formdata1 = new FormData(); let formdata2 = new FormData(); let formdata3 = new FormData(); formdata1.append("0","h23") formdata2.append("address1",formdata1

我正在尝试使用formdata发布嵌套值。我是这样尝试的:

const {phone} = this.state

      let formdata1 = new FormData();
      let formdata2 = new FormData();
      let formdata3 = new FormData();

      formdata1.append("0","h23")
      formdata2.append("address1",formdata1)
      formdata2.append("use_for_shipping",true)
      formdata2.append("first_name","isa")
      formdata2.append("last_name","annamyradow")
      formdata2.append("email","isaanna98@gmai.com")
      formdata2.append("city","ashgabat")
      formdata2.append("state","TKM")
      formdata2.append("postcode","110092")
      formdata2.append("country","TKM")
      formdata2.append("phone",{phone})

      formdata3.append("billing", formdata2)

      console.warn(JSON.stringify(formdata2))

       fetch(`http://arzan.com.tm/market/api/checkout/save-address`, {
          method: 'POST',
          headers: {
              'Accept': 'application/json',
              'Content-Type': 'application/json',
          },
          body: formdata2



      })

          .then((response) => response.json())
          .then((res) => {
            console.warn('zakaz:   '+JSON.stringify(res))
          })
          }

{
    "billing" :  {
        "address1" : { "0" : "h23" },
        "use_for_shipping" : "true",
        "first_name" : "john",
        "last_name" : "doe",
        "email" : "john@webkul.com",
        "city" : "noida",
        "state"  :"DL",
        "postcode" : "110092",
        "country" : "IN",
        "phone" : "8802097347"
    },
    "shipping" : {
        "address1" : {
        "0" : ""
        }
    }
}
我从未在react native中遇到过此对象结构。根据我对
formdata
的推断,我尝试了此对象结构。我知道存在一些不足。实际发布的数据结构应如下所示:

const {phone} = this.state

      let formdata1 = new FormData();
      let formdata2 = new FormData();
      let formdata3 = new FormData();

      formdata1.append("0","h23")
      formdata2.append("address1",formdata1)
      formdata2.append("use_for_shipping",true)
      formdata2.append("first_name","isa")
      formdata2.append("last_name","annamyradow")
      formdata2.append("email","isaanna98@gmai.com")
      formdata2.append("city","ashgabat")
      formdata2.append("state","TKM")
      formdata2.append("postcode","110092")
      formdata2.append("country","TKM")
      formdata2.append("phone",{phone})

      formdata3.append("billing", formdata2)

      console.warn(JSON.stringify(formdata2))

       fetch(`http://arzan.com.tm/market/api/checkout/save-address`, {
          method: 'POST',
          headers: {
              'Accept': 'application/json',
              'Content-Type': 'application/json',
          },
          body: formdata2



      })

          .then((response) => response.json())
          .then((res) => {
            console.warn('zakaz:   '+JSON.stringify(res))
          })
          }

{
    "billing" :  {
        "address1" : { "0" : "h23" },
        "use_for_shipping" : "true",
        "first_name" : "john",
        "last_name" : "doe",
        "email" : "john@webkul.com",
        "city" : "noida",
        "state"  :"DL",
        "postcode" : "110092",
        "country" : "IN",
        "phone" : "8802097347"
    },
    "shipping" : {
        "address1" : {
        "0" : ""
        }
    }
}

它给出了
无误的拒绝承诺
。有人能帮我吗

您使用了错误的内容类型来发送formdata,formdata的内容类型应为“multipart/form data”,而不是“application/json”。也可以考虑将数据发送为JSON.< /P>,可以向服务器添加一个catch并从服务器中查看错误吗?我尝试过,但是在最后,结果是相同的((内容类型应该是多部分的/形式的数据更改)