Regex 带引号和逗号的正则表达式模式

我正在试图找到正确的正则表达式，以便在文件中搜索由逗号分隔的双引号。例如，我试图找到

“2742734”

，然后在文本编辑器中替换它，将逗号改为每4个数字一个，这样最终结果将是

“2742734”

我尝试了一些我在SO上找到的例子，但是没有一个能像这样帮助我解决这个问题

"[^"]+"

'\d+'

虽然上面确实找到了匹配项，但我不知道如何处理逗号以及如何用什么替换它

---

谢谢你的帮助

可能有更好的方法，但我建议以下方法：

输入：

$ cat to_transform.txt
abc "27,422,734" def"27,422,734" def
ltu "123,734" abc "345,678,123,734" vtu
xtz "345,678,123,734" vtu "345,678,123,734"
u "1" a
"123"
iu"abc"a "123,734"

$ paste -d' ' <(grep -oP '(?<=")(:?\d+,\d+)+(?=")' to_transform.txt) <(grep -oP '(?<=")(:?\d+,\d+)+(?=")' to_transform.txt | sed -e 's/,//g;:loop s/\([0-9]\{4\}\)\($\|,\)/\2,\1/g; s/,,/,/g; /\([0-9]\{5\}\)/b loop') | awk '{cmd="sed -i 0,/"$1"/s/" $1 "/" $2 "/ to_transform.txt"; system(cmd)}'

$ cat to_transform.txt
abc "2742,2734" def"2742,2734" def
ltu "12,3734" abc "3456,7812,3734" vtu
xtz "3456,7812,3734" vtu "3456,7812,3734"
u "1" a
"123"
iu"abc"a "12,3734"

s/,//g #remove all , in the number
:loop  #create a label to loop
s/\([0-9]\{4\}\)\($\|,\)/\2,\1/g #add a coma after every chain of 4 characters starting by the end of the string/or from the latest coma added
s/,,/,/g #remove duplicate comas added by the previous step if any
/\([0-9]\{5\}\)/b loop #if there are at least 5 digits present successively in the string loop and continue the processing.

CMD:

$ cat to_transform.txt
abc "27,422,734" def"27,422,734" def
ltu "123,734" abc "345,678,123,734" vtu
xtz "345,678,123,734" vtu "345,678,123,734"
u "1" a
"123"
iu"abc"a "123,734"

$ paste -d' ' <(grep -oP '(?<=")(:?\d+,\d+)+(?=")' to_transform.txt) <(grep -oP '(?<=")(:?\d+,\d+)+(?=")' to_transform.txt | sed -e 's/,//g;:loop s/\([0-9]\{4\}\)\($\|,\)/\2,\1/g; s/,,/,/g; /\([0-9]\{5\}\)/b loop') | awk '{cmd="sed -i 0,/"$1"/s/" $1 "/" $2 "/ to_transform.txt"; system(cmd)}'

$ cat to_transform.txt
abc "2742,2734" def"2742,2734" def
ltu "12,3734" abc "3456,7812,3734" vtu
xtz "3456,7812,3734" vtu "3456,7812,3734"
u "1" a
"123"
iu"abc"a "12,3734"

s/,//g #remove all , in the number
:loop  #create a label to loop
s/\([0-9]\{4\}\)\($\|,\)/\2,\1/g #add a coma after every chain of 4 characters starting by the end of the string/or from the latest coma added
s/,,/,/g #remove duplicate comas added by the previous step if any
/\([0-9]\{5\}\)/b loop #if there are at least 5 digits present successively in the string loop and continue the processing.

代码详细信息和说明：

$ cat to_transform.txt
abc "27,422,734" def"27,422,734" def
ltu "123,734" abc "345,678,123,734" vtu
xtz "345,678,123,734" vtu "345,678,123,734"
u "1" a
"123"
iu"abc"a "123,734"

$ paste -d' ' <(grep -oP '(?<=")(:?\d+,\d+)+(?=")' to_transform.txt) <(grep -oP '(?<=")(:?\d+,\d+)+(?=")' to_transform.txt | sed -e 's/,//g;:loop s/\([0-9]\{4\}\)\($\|,\)/\2,\1/g; s/,,/,/g; /\([0-9]\{5\}\)/b loop') | awk '{cmd="sed -i 0,/"$1"/s/" $1 "/" $2 "/ to_transform.txt"; system(cmd)}'

$ cat to_transform.txt
abc "2742,2734" def"2742,2734" def
ltu "12,3734" abc "3456,7812,3734" vtu
xtz "3456,7812,3734" vtu "3456,7812,3734"
u "1" a
"123"
iu"abc"a "12,3734"

s/,//g #remove all , in the number
:loop  #create a label to loop
s/\([0-9]\{4\}\)\($\|,\)/\2,\1/g #add a coma after every chain of 4 characters starting by the end of the string/or from the latest coma added
s/,,/,/g #remove duplicate comas added by the previous step if any
/\([0-9]\{5\}\)/b loop #if there are at least 5 digits present successively in the string loop and continue the processing.

---

• 先决条件：您的输入符合“[0-9，]*”并且是“#，###”格式的正确数字
  
  #!/bin/bash
  colonmv () {
       echo $1 | sed -r 's/,([0-9]{3})+/\1/g;' | \
       rev | sed -r 's/[^0-9]?([0-9]{4})/\1,/g;s/,"$/"/;s/.*/"&/' | rev
  }
  
  colonmv '"734"'
  colonmv '"2,734"'
  colonmv '"22,734"'
  colonmv '"422,734"'
  colonmv '"7,422,734"'
  colonmv '"27,422,734"'
  colonmv '"127,422,734"'
  colonmv '"5,127,422,734"'
  
  测试：
  
  我发现了一个更短的解决方案（与gnu sed一起使用）：
  
  但是请注意，第一个sed命令会吃掉每个逗号，而不仅仅是数字之间的逗号，所以请在输入之前对其进行改进或过滤
  
  第二个命令使用：a技巧
  
  读取4位数字，然后用相同的加逗号的非数字（>）替换，当替换发生时，从ta跳回到：a并重复
  
  现在，让我们看看野外的科隆病毒：
  
  colonmv '"A 3-grouped, pretty long number: 5,127,422,734 and an ungrouped one 5678905567789065778"'
  "A 3-grouped pretty long number: 51,2742,2734 and an ungrouped one 567,8905,5677,8906,5778"
  
  你在bash/shell吗？你用什么工具来替换文本？哪种语言？@Allan:这很讽刺吗？：）我必须承认，我根本不熟悉贪婪的非贪婪前缀。可能是因为它们很新吗？迟早，我必须对他们有更多的了解。叹息.）不，没什么讽刺的，看看我的答案，太长了！就性能而言，我认为你的也不错！（我还必须在
  sed
  代码中循环，我多次调用
  sed
  ，并让
  awk
  处理一个临时文件，因此…@Allan:在
  734中找到了一个更短的文件。是
  “
  ”“
  输入错误？你看到了！不，试过了，这是命令的产物。我的新解决方案没有出现此错误。：）谢谢你的帮助！我终于明白了：）