Regex 将键和值置于哈希火箭的中心

使用vim表格，我尝试将其格式化如下：

foo = {
    "iSortCol_0" => "1",
    "sSortDir_0" => "desc",
  "iSortingCols" => "1",
   "bSortable_0" => "false",
   "bSortable_1" => "true",
   "bSortable_2" => "false",
   "bSortable_3" => "true",
   "bSortable_4" => "false",
   "bSortable_5" => "true",
   "bSortable_6" => "true",
   "bSortable_7" => "true",
   "bSortable_8" => "true"
}

foo = {
      "iSortCol_0" => "1",
"sSortDir_0" => "desc",
    "iSortingCols" =>"1",
     "bSortable_0" =>   "false",
     "bSortable_1" => "true",
     "bSortable_2"=> "false",
     "bSortable_3"  => "true",
     "bSortable_4"   => "false",
     "bSortable_5" => "true",
     "bSortable_6" =>    "true",
     "bSortable_7" =>"true",
     "bSortable_8" => "true"
}

我有一个随机格式化的ruby哈希表中的项目列表，例如：

foo = {
    "iSortCol_0" => "1",
    "sSortDir_0" => "desc",
  "iSortingCols" => "1",
   "bSortable_0" => "false",
   "bSortable_1" => "true",
   "bSortable_2" => "false",
   "bSortable_3" => "true",
   "bSortable_4" => "false",
   "bSortable_5" => "true",
   "bSortable_6" => "true",
   "bSortable_7" => "true",
   "bSortable_8" => "true"
}

foo = {
      "iSortCol_0" => "1",
"sSortDir_0" => "desc",
    "iSortingCols" =>"1",
     "bSortable_0" =>   "false",
     "bSortable_1" => "true",
     "bSortable_2"=> "false",
     "bSortable_3"  => "true",
     "bSortable_4"   => "false",
     "bSortable_5" => "true",
     "bSortable_6" =>    "true",
     "bSortable_7" =>"true",
     "bSortable_8" => "true"
}

我可以使用

Tab/=>

将其关闭，但它不能完全产生所需的结果：

foo = {
      "iSortCol_0" => "1",
"sSortDir_0"       => "desc",
    "iSortingCols" => "1",
     "bSortable_0" => "false",
     "bSortable_1" => "true",
     "bSortable_2" => "false",
     "bSortable_3" => "true",
     "bSortable_4" => "false",
     "bSortable_5" => "true",
     "bSortable_6" => "true",
     "bSortable_7" => "true",
     "bSortable_8" => "true"
}

---

如何指定对齐符号的左侧的格式？我想我需要使用

\zs

或

\ze

，但我很难将它们用于此目的

您需要为每个截面指定对齐方式：

Tabularize/=>/r1l1l0

右侧为

r

，左侧为

l

，中间为

c

。每个后接每个部分的空间数。因此，您在

=>

上拆分，这意味着

=>

前面有一个部分，

=>

本身，以及

=>

后面的文本部分

---

由于我不喜欢右对齐，您可能希望通过

=I}

缩进代码，然后执行

：制表/=>/

为什么与第二个

l

关联的整数无关紧要（即

制表/=>/r1l1l1

，

制表/=>/r1l2

，

制表/=>/r1l213

都产生相同的结果）？从

：h表格演练
：“字母后面的数字是在下一个字段开始之前要插入的空格数”。因为这是最后一个字段，所以它与您指定的空间大小无关，因为它不会被使用。那么为什么首先需要指定它呢。你能描述一下第二个
l
对整个语句的影响吗？我想这可能与以下事实有关：tabularize会在找到更多字段时重复对齐标志<第二个字段的code>l1
在
=>
后添加1个空格。您可以玩这个游戏并将其更改为0，然后看到
=>
和下面的文本将紧靠在一起。