Regex 正在查找名称年龄性别的正则表达式，中间必须有空格

这就是我所拥有的，但它不起作用。我没有犯错误，但我也没有得到结果，通过或失败

^[a-zA-Z]+(([\'\ \][(^10$|^[0-9]{1,2}]))+(([\'\ \][(?:m|M|f|F|)$]))*$

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首先，让我们看看您提到的模式将匹配什么：

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^[a-zA-Z]+(([\'\ \][(^10$|^[0-9]{1,2}]))+(([\'\ \][(?:m|M|f|F|)$]))*$
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Assert position at the beginning of the string «^»
Match a single character present in the list below «[a-zA-Z]+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
   A character in the range between “a” and “z” «a-z»
   A character in the range between “A” and “Z” «A-Z»
Match the regular expression below and capture its match into backreference number 1 «(([\'\ \][(^10$|^[0-9]{1,2}]))+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
   Note: You repeated the capturing group itself.  The group will capture only the last iteration.  Put a capturing group around the repeated group to capture all iterations. «+»
   Match the regular expression below and capture its match into backreference number 2 «([\'\ \][(^10$|^[0-9]{1,2}])»
      Match a single character present in the list below «[\'\ \][(^10$|^[0-9]{1,2}»
         Between one and 2 times, as many times as possible, giving back as needed (greedy) «{1,2}»
         A ' character «\'»
         A   character «\ »
         A ] character «\]»
         One of the characters “[(^10$|” «[(^10$|^[»
         A character in the range between “0” and “9” «0-9»
      Match the character “]” literally «]»
Match the regular expression below and capture its match into backreference number 3 «(([\'\ \][(?:m|M|f|F|)$]))*»
   Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
   Note: You repeated the capturing group itself.  The group will capture only the last iteration.  Put a capturing group around the repeated group to capture all iterations. «*»
   Match the regular expression below and capture its match into backreference number 4 «([\'\ \][(?:m|M|f|F|)$])»
      Match a single character present in the list below «[\'\ \][(?:m|M|f|F|)$]»
         A ' character «\'»
         A   character «\ »
         A ] character «\]»
         One of the characters “[(?:m|MfF)$” «[(?:m|M|f|F|)$»
Assert position at the end of the string (or before the line break at the end of the string, if any) «$»

很明显，该模式希望与上下文相匹配，如：

aaaa' ]'m

当您要匹配类似于

bob33m

的内容时，最简单的模式是：

  (?i)^[a-z]+ [0-9]+ [mf]+$

也就是说

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希望此能够帮助您理解主题。

如果我们没有关于输入、预期输出和您当前获得的输出的信息，我们无法真正帮助您。“它不工作”根本不是一个有用的问题描述。请使用此信息更新您的问题。非常感谢。再补充一句，你现在的表达显然是在寻找比“姓名年龄性别”更多的废话，所以输入行的例子是必不可少的。谢谢你的回答。基本上，我正在尝试在我的表单中创建一个字段来捕获姓名（最好是任何名字“a-z”，然后是一个一位数或两位数的年龄“0-9”，最后是“m”或“f”或“m”或“f”）。我更希望正则表达式在每个条件之间强制留一个空白。因此…Bob 33 M对不起，不工作的部分意味着在正则表达式测试仪中测试时，即使输入正确的模式，它也不会显示任何匹配。非常感谢Cylian！你不仅解释了正则表达式的一些工作，而且还帮助我完成了co德也是。你太棒了。我刚刚发现了一件事。我可以启用它来匹配由回车分隔的一行或多行吗？我已经尝试过了，但它只使用第一行（？I）^[a-z]+[0-9]+[mf]+\s$@user1756546:当然只要使用

（？im）^[a-z]+[0-9]+[mf]+\s$

取而代之。非常感谢塞利安！我要试一试。。。

"(?i)" &     ' Match the remainder of the regex with the options: case insensitive (i)
"^" &        ' Assert position at the beginning of the string
"[a-z]" &    ' Match a single character in the range between “a” and “z”
   "+" &        ' Between one and unlimited times, as many times as possible, giving back as needed (greedy)
"\ " &       ' Match the character “ ” literally
"[0-9]" &    ' Match a single character in the range between “0” and “9”
   "+" &        ' Between one and unlimited times, as many times as possible, giving back as needed (greedy)
"\ " &       ' Match the character “ ” literally
"[mf]" &     ' Match a single character present in the list “mf”
   "+" &        ' Between one and unlimited times, as many times as possible, giving back as needed (greedy)
"$"          ' Assert position at the end of the string (or before the line break at the end of the string, if any)