Rails/Rspec:我将如何测试?为了赛德基?

Rails/Rspec:我将如何测试?为了赛德基?,rspec,sidekiq,Rspec,Sidekiq,我有一个街区: def already_syncing? Sidekiq::Queue.new(queue_name).any? { |q| q.args[0] == car_id } end 我如何测试这个?如果我这样把它删掉: allow(Sidekiq::Queue).接收消息链(:new,:any?{true} 那么我的实际块中的条件就没有被测试。我想你要找的是: allow(Sidekiq::Queue)。接收消息链(:new,:any?)和产量() 以下是一些示例代码/规范(

我有一个街区:

def already_syncing?
  Sidekiq::Queue.new(queue_name).any? { |q| q.args[0] == car_id }
end
我如何测试这个?如果我这样把它删掉:

allow(Sidekiq::Queue).接收消息链(:new,:any?{true}


那么我的实际块中的条件就没有被测试。

我想你要找的是:

allow(Sidekiq::Queue)。接收消息链(:new,:any?)和产量()

以下是一些示例代码/规范(我不知道有哪些值/方法调用被删除),您可以自己尝试,并根据需要进行更改:

class SyncTest
  def already_syncing?
    Sidekiq::Queue.new(queue_name).any? { |q| q.args[0] == car_id }
  end

  private # values for these methods below arbitrarily defined

  def queue_name
    'test'
  end

  def car_id
    1
  end
end

RSpec.describe SyncTest do
  let(:sync_test) { described_class.new }

  describe '#already_syncing?' do
    let(:queue) { double('queue') }
    let(:already_syncing) { sync_test.already_syncing? }

    before do
      # I don't have Sidekiq available for testing, so just say
      # it's a generic class.
      stub_const('Sidekiq::Queue', Class.new)
      allow(Sidekiq::Queue).to \
        receive_message_chain(:new, :any?).and_yield(queue)
    end

    context "when queue's args[0] == car_id" do
      before do
        allow(queue).to receive(:args).and_return([1])
      end

      it 'returns true' do
        expect(already_syncing).to be true
      end
    end

    context "when queue's args[0] != car_id" do
      before do
        allow(queue).to receive(:args).and_return([0])
      end

      it 'returns false' do
        expect(already_syncing).to be false
      end
    end
  end
end