Ruby on rails 添加到收藏夹时，为什么在控制器中遇到SQLite3:：ConstraintException？偏爱基于Hartl教程的micropost

我的最爱是基于Hartl的follow user按钮

我可以进入用户页面并喜欢一个micropost，但只要我尝试喜欢一秒钟，就会在

favoritescontroller\create

中给我一个

SQLite3:：ConstraintException

。约束条件是：

UNIQUE constraint failed: favourites.favouriter_id, favourites.favourited_id.

为什么我会遇到这种限制

收藏夹管理员：

class FavouritesController < ApplicationController
before_action :logged_in_user

def create
@micropost = Micropost.find(params[:favourited_id])
current_user.favourite(@micropost)
redirect_to user_path (current_user)
end

def destroy
@micropost = Favourite.find(params[:id]).favourited
current_user.unfavourite(@micropost)
redirect_to user_path (current_user)
end  

end

def favouriting
@title = "Favourites"
@user = User.find(params[:id])
@microposts = @user.favouriting.paginate(page: params[:page])
render 'microposts/show_favourite'
end  

def favouriter
@title = "Favourite"
@micropost = Micropost.find(params[:id])
@users = @micropost.favouriter.paginate(page: params[:page])
render 'microposts/show_favourite'
end 

用户控制器：

class FavouritesController < ApplicationController
before_action :logged_in_user

def create
@micropost = Micropost.find(params[:favourited_id])
current_user.favourite(@micropost)
redirect_to user_path (current_user)
end

def destroy
@micropost = Favourite.find(params[:id]).favourited
current_user.unfavourite(@micropost)
redirect_to user_path (current_user)
end  

end

def favouriting
@title = "Favourites"
@user = User.find(params[:id])
@microposts = @user.favouriting.paginate(page: params[:page])
render 'microposts/show_favourite'
end  

def favouriter
@title = "Favourite"
@micropost = Micropost.find(params[:id])
@users = @micropost.favouriter.paginate(page: params[:page])
render 'microposts/show_favourite'
end 

微观模型：

class Micropost < ActiveRecord::Base
belongs_to :user

has_many :favourites, class_name: "Favourite",foreign_key: "favourited_id", dependent: :destroy
has_many :favouriter, through: :favourites, source: :favouriter

class Micropost

您似乎将用户id作为收藏夹id传递，这对我来说没有意义。这有意义，因为当我喜欢一个微博客时，它喜欢所有用户的微博客，而不是一个。如何使最微小的id成为最受欢迎的id？