Ruby on rails 内部联接上的Rails ActiveRecord子查询

我正在努力使用Rails的ActiveRecord查询接口来复制具有内部联接子查询的查询。我将如何复制以下内容：

SELECT ass.name, COUNT(DISTINCT a.question_id) AS 
  answered_questions, tq.total_questions
  FROM assessments AS ass
  INNER JOIN  (SELECT ass.id, COUNT(q.id) AS total_questions FROM                         
    questions AS q INNER JOIN assessments AS ass ON ass.id=q.assessment_id 
    GROUP BY 
    ass.id) as tq ON tq.id=ass.id
  INNER JOIN questions AS q ON q.assessment_id=ass.id
  INNER JOIN answers AS a ON a.assessment_id=ass.id AND a.question_id=q.id
  INNER JOIN org_assesments AS oa ON ass.id=oa.assessment_id
  INNER JOIN users AS u ON oa.org_id=u.org_id AND       
    a.user_id=u.id
  WHERE  u.id=1
  GROUP BY ass.name, tq.total_questions
  ORDER BY ass.created_at DESC
  LIMIT 10

我似乎无法使用查询生成器将其用于子查询。在没有子查询的情况下，我有这样一个功能，它可以为我提供评估标题和回答的问题数量：

Question.joins(:assessment => {:org_assessments => {:org => :users}}).joins(:answers)
                 .where(answers:{:user_id => params[:id]})
                 .distinct('answers.question_id').group(['assessments.name']).count()

---

如何编写此命令以将子查询包含在上面的原始SQL中？

您可以将子查询作为字符串发送到

连接方法：

subquery =
  TotalQuestion.
    joins(:assessments).
    group('assessments.id').
    select('assessments.id, COUNT(q.id) as total_questions').to_sql

Question.joins("(#{sub_query}) as tq on tq.id=ass.id")

您可以将其与查询的其他部分组合：

Question.
    joins(:assessment => {:org_assessments => {:org => :users}}).joins(:answers).
    joins("(#{sub_query}) as tq on tq.id=ass.id").
    where(answers:{:user_id => params[:id]}).
    distinct('answers.question_id').group(['assessments.name']).count()

这不应该从
评估。加入开始吗？
？这是否有效
评估。通过sql（“上面的查询”）查找？
？我认为你应该查询评估而不是问题，比如：->评估。加入（：问题，：答案，组织评估：：用户）。其中（用户：{id:1}）。不同（'answers.question\u id'）。组（['Assessment.name'）。顺序（'assessments.created_at DESC'）.count（）