Ruby 将字符串拆分为N个字符的子字符串
我只是想知道是否有更好的方法将字符串拆分为N个字符的子字符串:Ruby 将字符串拆分为N个字符的子字符串,ruby,Ruby,我只是想知道是否有更好的方法将字符串拆分为N个字符的子字符串: "something" (by 4 characters) -> ["some", "omet", "meth", "ethi", "thin", "hing"] 这是我的密码: n = 4 s = "something" result = [] 0.upto(s.size - n) do | idx | result << s[idx..idx+n-1] end p result 可能将拆分//替
"something" (by 4 characters) -> ["some", "omet", "meth", "ethi", "thin", "hing"]
这是我的密码:
n = 4
s = "something"
result = []
0.upto(s.size - n) do | idx |
result << s[idx..idx+n-1]
end
p result
可能将拆分//替换为字符。可能将拆分//替换为字符。
"something".chars.each_cons(4).map(&:join)
=> ["some", "omet", "meth", "ethi", "thin", "hing"]