Ruby 有没有一种方法可以说匹配定义的子序列/分组的一个或多个实例?
我不知道“不同”,但是:Ruby 有没有一种方法可以说匹配定义的子序列/分组的一个或多个实例?,ruby,regex,Ruby,Regex,我不知道“不同”,但是: require 'rubygems' require 'differ' original = "Epic lolcat fail bellmead drive!" current = "Epic wolfman fail bellmead dr!" diff = Differ.diff_by_word(current, original).to_s puts diff # => "Epic {"lolcat" >> "wolfman
require 'rubygems'
require 'differ'
original = "Epic lolcat fail bellmead drive!"
current = "Epic wolfman fail bellmead dr!"
diff = Differ.diff_by_word(current, original).to_s
puts diff # => "Epic {"lolcat" >> "wolfman"} fail bellmead {"drive" >> "dr"}!
diff =~ /(\{"[a-zA-Z0-9]*" >> "[a-zA-Z0-9s]*"\})/
puts "#{$1} to #{$2} #{$3} to #{$4}"
# => lolcat to wolfman to
# Desired output: lolcat to wolfman to drive to dr
嗯…扫描会传回一个数组,不是吗。是的,的确如此。谢谢你,阿德里安。
require 'rubygems'
require 'differ'
original = "Epic lolcat fail bellmead drive!"
current = "Epic wolfman fail bellmead dr!"
diff = Differ.diff_by_word(current, original).to_s
puts diff # => "Epic {"lolcat" >> "wolfman"} fail bellmead {"drive" >> "dr"}!
captures = diff.scan /\{"([a-zA-Z0-9]*)" >> "([a-zA-Z0-9s]*)"\}/
captures.each {|c| puts "#{c[0]} to #{c[1]}" }