Ruby 如何按特定格式拆分多级数组

我有一个数组如下

#bad
tourney = [
  [
    [["Armando", "P"], ["Dave", "S"]],      
    [["Richard", "R"], ["Michael", "S"]]
  ],
  [
    [["Allen", "S"], ["Omer", "P"]],
    [["David E.", "R"], ["Richard X.", "P"]]
  ]
]

我必须实现一个递归的竞赛方法，让每个竞争者互相竞争。只要是2^n，本次比赛就必须增加到任何数字。是否有任何数组方法可以像下面的数组那样将此数组分为两个级别

#good
tourney = [
  ["Armando", "P"], ["Dave", "S"],
  ["Richard", "R"], ["Michael", "S"],
  ["Allen", "S"], ["Omer", "P"],
  ["David E.", "R"], ["Richard X.", "P"]
]

有了这个，我可以使用

每个_片（2）

来让对手彼此对抗

---

解决了的 下面是我能想到的

def split(array)
  return array.flatten(1)
end

def depth_array(a)
  return 0 unless a.is_a?(Array)
  return 1+depth_array(a[0])
end

def format_array(array)
  good = array
  while depth_array(good) > 2
    good = split(good)
  end
end

tourney = [[[["Armando", "P"], ["Dave", "S"]],      

       [["Richard", "R"], ["Michael", "S"]]],

       [[["Allen", "S"], ["Omer", "P"]],

       [["David E.", "R"], ["Richard X.", "P"]]]]

tourney2 = [[["Armando", "P"], ["Dave", "S"]], 

        [["Allen", "S"], ["Omer", "P"]]]

tourney3 = [["Omer", "P"], ["Allen", "S"]]

tourney4 = [[[[["Armando", "P"], ["Armando", "P"]], [["Armando", "P"], ["Armando", "P"]]], 

         [[["Allen", "S"], ["Allen", "S"]], [["Allen", "S"], ["Allen", "S"]]]], 

         [[[["Dave", "S"], ["Dave", "S"]], [["Dave", "S"], ["Dave", "S"]]], 

          [[["David E.", "R"], ["David E.", "R"]], [["David E.", "R"], ["David E.", "R"]]]]]



format_array(tourney4)

---

像这样的怎么样：

tourney = [[[["Armando", "P"], ["Dave", "S"]],      
           [["Richard", "R"], ["Michael", "S"]]],
           [[["Allen", "S"], ["Omer", "P"]],
           [["David E.", "R"], ["Richard X.", "P"]]]]

good = [].tap do |arr|
  tourney.flatten.each_slice(2) do |pr|
    arr << pr
  end
end

puts good.inspect

# output 
[["Armando", "P"], ["Dave", "S"], ["Richard", "R"], ["Michael", "S"], ["Allen", "S"], ["Omer", "P"], ["David E.", "R"], ["Richard X.", "P"]]

tourney=[[“Armando”，“P”]，[“Dave”，“S”]，
[Richard]，[R]，[Michael]，[S]，
[Allen]、[S]、[Omer]、[P]，
[David E.，“R”]，[Richard X.，“P”]]
好=[]点击do | arr|
锦标赛。整平。每片（2）做|
arr
锦标赛。展平（2）
将坏阵型变为好阵型。
您正在寻找
阵型#展平
。。。它可能会走得太远（太平），但它可能会让你走上正确的轨道。这似乎是一个“原始”痴迷的案例。如果“最低级别”对是对象（即[“Allen”，“S”]是数组以外的对象），那么展平将是最简单的方法。我将尝试此方法，但如果说比赛中有16人，我可能必须能够做同样的事情，并且设置方式相同。因此，我必须处理更多的层。由于我必须能够将任意数量的竞争对手置于2的幂下，因此我决定最好将（1）展平，直到阵列的深度等于2，这是我所需的深度。