Rust 如何获取从最小值到最大值（含最小值）的随机数

gen_Range a，b可以获得从a到b的随机数，但不包括b。 如果我写gen_range-21474836482147483648，它就不能工作，因为gen_range->i32，i32

那么，我该怎么办

您也可以将Uniform:：fromstd:：i32:：MIN..=std:：i32:：MAX与inclusive range一起使用，如果重复从同一范围进行采样，速度会更快： 使用数组填充：rng.fill&mut a； 使用[i]=rng.gen 阵列构造len有什么问题？

use rand::Rng;
fn main() {
    let mut zz = rand::thread_rng();
    let mut a: [i32; 4096] = [0; 4096];
    for n in 0..4096 {
        a[n] = zz.gen_range(-2147483648,2147483647);
    }
    ......
}

use rand::distributions::{Distribution, Uniform};
fn main() {
    let between = Uniform::from(std::i32::MIN..=std::i32::MAX);
    let mut rng = rand::thread_rng();
    let mut a = [0_i32; 4096];
    for i in 0..4096 {
        a[i] = between.sample(&mut rng);
    }
    println!("{} {}", a.iter().min().unwrap(), a.iter().max().unwrap());
}

use rand::{thread_rng, Rng};
fn main() {
    let mut rng = thread_rng();
    let mut a = [0_i32; 4096];
    rng.fill(&mut a); // array fill
    println!("{} {}", a.iter().min().unwrap(), a.iter().max().unwrap());
}

use rand::{thread_rng, Rng};
fn main() {
    let mut rng = thread_rng();
    let mut a = [0_i32; 4096];
    for i in 0..4096 {
        a[i] = rng.gen();
    }
    println!("{} {}", a.iter().min().unwrap(), a.iter().max().unwrap());
}

let a: [i32; 32] = rng.gen();

a[i] = rng.gen_range(-2_147_483_648_i64, 2_147_483_648_i64) as i32;

use rand::Rng;
fn main() {
    let mut rng = rand::thread_rng();
    let mut a = [0_i32; 4096];
    for i in 0..4096 {
        a[i] = rng.gen_range(-2_147_483_648_i64, 2_147_483_648_i64) as i32;
    }
    println!("{} {}", a.iter().min().unwrap(), a.iter().max().unwrap());
}