捕获已解析的SASS父选择器
我试图找到一种方法来捕获SASS(运行3.2.3)中解析的父选择器(捕获已解析的SASS父选择器,sass,Sass,我试图找到一种方法来捕获SASS(运行3.2.3)中解析的父选择器(&),很可能是在mixin中 不幸的是(我发现在github上对此进行了讨论),以下go-to解决方案不起作用: @mixin append-to-captured-parent($append) { $selector: "&-#{$append}"; #{$selector} { @content; } } .foo { @include append-to-captured-parent(
&
),很可能是在mixin中
不幸的是(我发现在github上对此进行了讨论),以下go-to解决方案不起作用:
@mixin append-to-captured-parent($append) {
$selector: "&-#{$append}";
#{$selector} { @content; }
}
.foo {
@include append-to-captured-parent("bar") {
color: blue;
}
}
所需输出为:
.foo .foo-bar { color: blue; }
是否有任何黑客或变通方法可以产生所需的输出?据我所知,这很可能是不可能的,因为直到SASS解析器构建了整个节点树,父选择器才被解析,在这一点上它遇到了&-bar{…}
,它就死了:
Syntax error: Invalid CSS after "&": expected "{", was "-bar"
我们能欺骗SASS先发制人地解决这个问题吗
注意:我非常愿意接受可以实现这一点的SASS扩展(Ruby-libs);不幸的是,目前我还没有足够的Ruby知识来开发自己的Ruby(不过我正在开发)嗯,我已经想出了一个解决办法 这种方法仅仅隔离了预期的功能,并独立于实际的层次结构对其进行管理 首先,一些快速实用程序:
@function slice($list, $from, $into) {
$result: ();
@for $index from $from through $into {
$result: append($result, nth($list, $index));
}
@return $result;
}
@function implode($list, $separator) {
$result: nth($list, 1);
@for $index from 2 through length($list) {
$result: #{$result}#{$separator}#{nth($list, $index)};
}
@return $result;
}
然后勇气:
$-class: ();
@function get-class() {
$top: if(length($-class) - 2 < 1, 1, length($-class) - 2);
@return implode(slice($-class, $top, length($-class)), "-");
}
@mixin class($name) {
$-class: append($-class, $name);
.#{get-class()} {
@content;
}
$-class: slice($-class, 1, length($-class) - 1);
}
将产生:
.foo { color: red; }
.foo .foo-bar { color: blue; }
一个不那么简单的例子是:
@include class(list) {
test: "list";
@include class(item) {
test: "item";
@include class(heading) {
test: "heading";
}
@include class(content) {
test: "content";
@include class(graphic) {
test: "graphic";
}
@include class(summary) {
test: "summary";
}
@include class(details) {
test: "details";
}
}
@include class(footing) {
test: "footing";
}
}
}
制作:
.list { test: "list"; }
.list .list-item { test: "item"; }
.list .list-item .list-item-heading { test: "heading"; }
.list .list-item .list-item-content { test: "content"; }
.list .list-item .list-item-content .item-content-graphic { test: "graphic"; }
.list .list-item .list-item-content .item-content-summary { test: "summary"; }
.list .list-item .list-item-content .item-content-details { test: "details"; }
.list .list-item .list-item-footing { test: "footing"; }
@法院Nah;这是在黑暗中拍摄的。正如我所提到的,似乎解析器在使用无效语法后会执行父选择器替换。@好吧,我已经用解决方法回答了我的问题;看看你是否感兴趣。
.list { test: "list"; }
.list .list-item { test: "item"; }
.list .list-item .list-item-heading { test: "heading"; }
.list .list-item .list-item-content { test: "content"; }
.list .list-item .list-item-content .item-content-graphic { test: "graphic"; }
.list .list-item .list-item-content .item-content-summary { test: "summary"; }
.list .list-item .list-item-content .item-content-details { test: "details"; }
.list .list-item .list-item-footing { test: "footing"; }