Scalaz迭代器,为BufferedReader创建枚举器

Scalaz迭代器,为BufferedReader创建枚举器,scala,scalaz,Scala,Scalaz,如何为BufferedReader创建枚举器 我发现了一篇相当旧的文章:它似乎不适用于Scalaz6.0.4 我尝试根据以下示例创建枚举器: 但我不明白如何将IO monad与Enumerator结合起来鲁纳尔的文章怎么了?以下版本适用于我(Scalaz 6.0.4): objectfileiteratee{ def enumReader[A](r:BufferedReader,it:IterV[String,A]):IO[IterV[String,A]={ def循环:IterV[String

如何为BufferedReader创建枚举器

我发现了一篇相当旧的文章:它似乎不适用于Scalaz6.0.4

我尝试根据以下示例创建枚举器:


但我不明白如何将IO monad与Enumerator结合起来

鲁纳尔的文章怎么了?以下版本适用于我(Scalaz 6.0.4):

objectfileiteratee{
def enumReader[A](r:BufferedReader,it:IterV[String,A]):IO[IterV[String,A]={
def循环:IterV[String,A]=>IO[IterV[String,A]={
案例i@Done(u,u)=>i.pure[IO]
案例i@Cont(k) =>用于{
IO[C]:IO[C]=
为了{

a谢谢,它很管用!但据我所知,scalaz的进化,从6版开始,更方便的方法是提供枚举器
 implicit val ListEnumerator = new Enumerator[List] {
   def apply[E, A](e: List[E], i: IterV[E, A]): IterV[E, A] = e match {
      case List() => i
      case x :: xs => i.fold(done = (_, _) => i,
                       cont = k => apply(xs, k(El(x))))
   }
 }
object FileIteratee {
  def enumReader[A](r: BufferedReader, it: IterV[String,  A]) : IO[IterV[String,  A]] = {
    def loop: IterV[String,  A] => IO[IterV[String,  A]] = {
      case i@Done(_, _) => i.pure[IO]
      case i@Cont(k) => for {
        s <- r.readLine.pure[IO]
        a <- if (s == null) i.pure[IO] else loop(k(El(s)))
      } yield a
    }
    loop(it)
  }

  def bufferFile(f: File) = new BufferedReader(new FileReader(f)).pure[IO]

  def closeReader(r: Reader) = r.close().pure[IO]

  def bracket[A,B,C](init: IO[A], fin: A => IO[B], body: A => IO[C]): IO[C] =
    for {
      a <- init
      c <- body(a)
      _ <- fin(a)
    } yield c

  def enumFile[A](f: File,  i: IterV[String,  A]) : IO[IterV[String, A]] =
    bracket(bufferFile(f),
            closeReader(_: BufferedReader),
            enumReader(_: BufferedReader,  i))
}