Scala 如何在匹配模式中获取case类的匹配实例

请看下面的代码：

  def receive: Receive = {
    case Begin(msg, expectedReply, signalSuccessWith, replyTo, receiver, pause) => {
      receiver ! msg
      val cancelHandle = context.system.scheduler.schedule(pause, pause, context.self, Retry)
      context.become(runtime(Begin(msg, expectedReply, signalSuccessWith, replyTo, receiver, pause), cancelHandle))
    }
    case _ =>
  }

您可以看到，在调用

context.been

时，我必须完全复制case class

Begin

的值，即传递其全部参数。这是可行的，但在我看来，这是代码的重复。有没有办法以某种方式获取匹配的值并将其传递出去？

如下所示：

def receive: Receive = {
  case fullMsg @ Begin(msg, expectedReply, signalSuccessWith, replyTo, receiver, pause) => {
    receiver ! msg
    val cancelHandle = context.system.scheduler.schedule(pause, pause, context.self, Retry)
    context.become(runtime(fullMsg, cancelHandle))
  }
  case _ =>
}

就像这样：

def receive: Receive = {
  case fullMsg @ Begin(msg, expectedReply, signalSuccessWith, replyTo, receiver, pause) => {
    receiver ! msg
    val cancelHandle = context.system.scheduler.schedule(pause, pause, context.self, Retry)
    context.become(runtime(fullMsg, cancelHandle))
  }
  case _ =>
}