Scala 基本特征是什么

只是在做一个概念验证库。尝试尽可能地抽象和混合特征，而不是继承，同样，在这个库中，所有角色实例之间实际上只有一个共同特征，根本没有类对象，只是混合特征来构建case对象。试图制作一个智能的ish-toString实现，它识别出我加入的特性，并相应地改变toString。我目前的理论是这样的：

//Completely wrong, just a rough pseudocode of one potential ideal
implicit class CharImpl[A <: Character](a: A){

  def toString:String = {
    for(
      i ← _:HasName ⇒ s"Name: ${a.name}"
      j ← _:HasAbbreviation ⇒ s"Abbreviation: ${a.castTo[HasAbbreviation].abbreviation}"
      k ← _:HasUnicode ⇒ s"Unicode: ${a.castTo[HasUnicode].unicode}"
      l ← _:HasDecimal ⇒ s"Decimal: ${a.castTo[HasDecimal].decimal}"
    ) {(i,j,k,l) mkString "\n"}
  }
}

//完全错误，只是一个潜在理想的粗略伪代码
隐式类CharImpl[A如何使用
super.toString
加上一些新的内容来重写
toString

trait A { override def toString: String = super.toString + " with A" }

trait B { override def toString: String = super.toString + " with B" }

trait C { override def toString: String = super.toString + " with C" }

class D { override def toString: String = super.toString + " D" }

scala> new D with C with A
res0: D with C with A = $anon$1@4df5014e D with C with A

scala> new D with C with B
res1: D with C with B = $anon$1@29042f37 D with C with B

class E extends C with A { override def toString: String = "E " + super.toString }

scala> new E
res3: E = E E@40145d8e with C with A

使用
super.toString
加上一些新的内容覆盖
toString
怎么样

trait A { override def toString: String = super.toString + " with A" }

trait B { override def toString: String = super.toString + " with B" }

trait C { override def toString: String = super.toString + " with C" }

class D { override def toString: String = super.toString + " D" }

scala> new D with C with A
res0: D with C with A = $anon$1@4df5014e D with C with A

scala> new D with C with B
res1: D with C with B = $anon$1@29042f37 D with C with B

class E extends C with A { override def toString: String = "E " + super.toString }

scala> new E
res3: E = E E@40145d8e with C with A

使用
super.toString
加上一些新的内容覆盖
toString
怎么样

trait A { override def toString: String = super.toString + " with A" }

trait B { override def toString: String = super.toString + " with B" }

trait C { override def toString: String = super.toString + " with C" }

class D { override def toString: String = super.toString + " D" }

scala> new D with C with A
res0: D with C with A = $anon$1@4df5014e D with C with A

scala> new D with C with B
res1: D with C with B = $anon$1@29042f37 D with C with B

class E extends C with A { override def toString: String = "E " + super.toString }

scala> new E
res3: E = E E@40145d8e with C with A

使用
super.toString
加上一些新的内容覆盖
toString
怎么样

trait A { override def toString: String = super.toString + " with A" }

trait B { override def toString: String = super.toString + " with B" }

trait C { override def toString: String = super.toString + " with C" }

class D { override def toString: String = super.toString + " D" }

scala> new D with C with A
res0: D with C with A = $anon$1@4df5014e D with C with A

scala> new D with C with B
res1: D with C with B = $anon$1@29042f37 D with C with B

class E extends C with A { override def toString: String = "E " + super.toString }

scala> new E
res3: E = E E@40145d8e with C with A

我从来不知道super调用了所有toString方法。我以为它只调用了1，除非指定。谢谢你的帮助。我最后稍微修改了一下，但效果很好！我从来不知道super调用了所有toString方法。我以为它只调用了1，除非指定。谢谢你的帮助。我最后稍微修改了一下，但效果很好！我从来都不知道super调用了所有toString方法。我以为它只调用了1，除非指定。谢谢你的帮助。我最后稍微修改了一下，但效果很好！我从来都不知道super调用了所有toString方法。我以为它只调用了1，除非指定。谢谢你的帮助。我最后稍微修改了一下，但效果很好。greaT