Snowflake cloud data platform 在Snowflake中查询变量数据

下面是我在示例中使用的数据变量源表。我想做一个查询，将这个数据从一个变量src解析到一个雪花表中

{
    "col1": bool,
    "col2": null,
    "col3": "datetime",
    "col4": int,
    "col5": "string",
    "col6": "string",
    "array": [
        {
            "x": bool,
            "y": null,
            "v": "datetime",
            "z": int,
           "w": "string",
            "q": "string",
            "obj": {
                    "a": "bool",
                     "b": "float"
                   },
    "col7": "datetime"
}
]
}

--这是我试过的

SELECT 

     src:col1::string as col1,
     src:col2::string as col2,
     src:col3::string as col3,
     src:col4::string as col4,
     src:col5::string as col5,
     src:col6::string as col6,

     s.value:x::string as S_x,
     s.value:y::string as s_y,
     s.value:v::string as s_v,
     s.value:z::string as s_z,
     s.value:w::string as s_w,
     s.value:q::string as s_q,

     s.value:obj.value:a::string as s_obj_a,
     s.value:obj.value:b::string as s_obj_b,

     src:col7::string as col7 
FROM tblvariant
    , table(flatten(src:s)) s
    ;

除了这两列（a，b）为空，而它们应该包含它们的数据之外，其他一切都正常工作。 有什么建议吗？

---

非常感谢

示例JSON与SQL不匹配。“阶段”和“元数据”在哪里？无论如何，这个问题似乎与额外的“值”关键字有关

create or replace table tblvariant ( src variant )
as select parse_json (' 
{
    "col1": "bool",
    "col2": null,
    "col3": "datetime",
    "col4": "int",
    "col5": "string",
    "col6": "string",
    "stages": [
        {
            "x": "bool",
            "y": null,
            "v": "datetime",
            "z": "int",
           "w": "string",
            "q": "string",
            "obj": {
                    "a": "bool",
                     "b": "float"
                   },
    "col7": "datetime"
}
]
}' );

如您所见，我修改了示例JSON并将“array”重命名为“stages”（根据您的SQL）。此SQL检索a和b的值：

SELECT 
     src:col1::string as col1,
     src:col2::string as col2,
     src:col3::string as col3,
     src:col4::string as col4,
     src:col5::string as col5,
     src:col6::string as col6,
     s.value:x::string as S_x,
     s.value:y::string as s_y,
     s.value:v::string as s_v,
     s.value:z::string as s_z,
     s.value:w::string as s_w,
     s.value:q::string as s_q,

     s.value:obj.a::string as s_obj_a,
     s.value:obj.b::string as s_obj_b,

     src:col7::string as col7 
FROM tblvariant
   , table(flatten(src:stages)) s
   -- , table(flatten(s.value:metadata)) m
    ;

---

示例JSON与SQL不匹配。“阶段”和“元数据”在哪里？无论如何，这个问题似乎与额外的“值”关键字有关

create or replace table tblvariant ( src variant )
as select parse_json (' 
{
    "col1": "bool",
    "col2": null,
    "col3": "datetime",
    "col4": "int",
    "col5": "string",
    "col6": "string",
    "stages": [
        {
            "x": "bool",
            "y": null,
            "v": "datetime",
            "z": "int",
           "w": "string",
            "q": "string",
            "obj": {
                    "a": "bool",
                     "b": "float"
                   },
    "col7": "datetime"
}
]
}' );

如您所见，我修改了示例JSON并将“array”重命名为“stages”（根据您的SQL）。此SQL检索a和b的值：

SELECT 
     src:col1::string as col1,
     src:col2::string as col2,
     src:col3::string as col3,
     src:col4::string as col4,
     src:col5::string as col5,
     src:col6::string as col6,
     s.value:x::string as S_x,
     s.value:y::string as s_y,
     s.value:v::string as s_v,
     s.value:z::string as s_z,
     s.value:w::string as s_w,
     s.value:q::string as s_q,

     s.value:obj.a::string as s_obj_a,
     s.value:obj.b::string as s_obj_b,

     src:col7::string as col7 
FROM tblvariant
   , table(flatten(src:stages)) s
   -- , table(flatten(s.value:metadata)) m
    ;

s、 值：obj。值：a：字符串为s_obj_a

s、 值：obj。值：b：字符串为s_obj_b

可以使用来访问对象的键。您无需使用来访问这些字段：

s.value:metadata.a:：字符串作为s\m\u a，
s、 值：metadata.b:：字符串为s_m_b，

您也不需要在

阶段

数组中的

元数据

对象上运行一秒钟，除非您确实需要每个

元数据

键有一个排他行，假设

元数据

是对象类型而不是嵌套数组。如果您只想将值提取到与每个数组行相同的级别，那么使用上面的方法就足够了

s、 值：obj。值：a：字符串为s_obj_a

s、 值：obj。值：b：字符串为s_obj_b

可以使用来访问对象的键。您无需使用来访问这些字段：

s.value:metadata.a:：字符串作为s\m\u a，
s、 值：metadata.b:：字符串为s_m_b，

您也不需要在

阶段

数组中的

元数据

对象上运行一秒钟，除非您确实需要每个

元数据

键有一个排他行，假设

元数据

是对象类型而不是嵌套数组。如果您只想将值提取到与每个数组行相同的级别，那么使用上面的方法就足够了