Snowflake cloud data platform 将字符串和输出拆分为行
我想根据分隔符“”拆分字符串,并将结果放入行中。因此,我试图在Snowflake中使用Snowflake cloud data platform 将字符串和输出拆分为行,snowflake-cloud-data-platform,Snowflake Cloud Data Platform,我想根据分隔符“”拆分字符串,并将结果放入行中。因此,我试图在Snowflake中使用SPLIT_to_TABLE函数,但没有成功 我使用regexp\u replace来清理字符串。如何将其输出到每个id的行中 SELECT value, TRIM(regexp_replace(value, '[{}_]', ' ')) AS extracted 以下是示例数据: +--------+------------------------------------+ | id
SPLIT_to_TABLE
函数,但没有成功
我使用regexp\u replace
来清理字符串。如何将其输出到每个id的行中
SELECT value,
TRIM(regexp_replace(value, '[{}_]', ' ')) AS extracted
以下是示例数据:
+--------+------------------------------------+
| id | value |
+--------+------------------------------------+
| fsaf12 | {Other Questions,Missing Document} |
| sfas11 | {Other} |
+--------+------------------------------------+
+--------+------------------+
| id | extracted |
+--------+------------------+
| fsaf12 | Other Questions |
| fsaf12 | Missing Document |
| sfas11 | Others |
+--------+------------------+
预期结果:
+--------+------------------------------------+
| id | value |
+--------+------------------------------------+
| fsaf12 | {Other Questions,Missing Document} |
| sfas11 | {Other} |
+--------+------------------------------------+
+--------+------------------+
| id | extracted |
+--------+------------------+
| fsaf12 | Other Questions |
| fsaf12 | Missing Document |
| sfas11 | Others |
+--------+------------------+
这里是答案,使用了replace函数而不是regexp\u replace 数据表(ID,VALUEA)为 ( 从值('fsaf12'、'{Other Questions,Missing Document}')、('sfas11'、'{Other}'中选择*) )
选择ID,REPLACE(REPLACE(VALUE,'{','','}','')从DATATABLE拆分的_值,横向拆分_到_表(VALUEA,',') 添加另一种拆分数据并将其输出为行的方法:
SELECT b,TRIM(regexp_replace(splitvalue, '[{}_]', '')) AS extracted from
(SELECT b, C.value::string AS splitvalue
FROM split,
LATERAL FLATTEN(input=>split(a, ',')) C);
其中a和b为表“拆分”中的列,数据如下:
A.
B
{第一,第二}
第1行
{第三,第四}
第2行