Snowflake cloud data platform 用阵列和dict混合的方法横向展平雪管数据

我有两个不同的结构化json文件，它们是从一个雪管中导入的。唯一的区别是它没有嵌套dict，而是有许多嵌套数组。我正在试图找出如何将结构1转换为一个最终确定的表。我已经成功地将结构2转换为一个表，并包含了下面的代码

我知道我需要利用横向展平，但没有成功

**Structure 1: Nested Arrays (Need help on)**
This json lives within a table and in column **JSONTEXT**
[
  {
    "ID": "xxx-xxxx-xxxx xxx-xxx",
    "caseTypeID": "xx-xxxx-xxxx-xxxxx",
    "content": {
      "AccountID": "xx-xxxxx-xxxx-xxxx xxxx-xxxxx",
      "AccountName": "XXXX",
      "Address": {
        "pxObjClass": "Data-Address-Postal"
      },
      "Addresses": [],
      "AllKickoffsComplete": "true",
      "BillingContactList": [],
      "ClientCurrency": "USD",
      "ClientID": "XXXXXX",
      "ClientNSID": "XXXXXXXX-00",
      "ClientName": "XXXXX XXXX Inc.",
      "CompanyPhoneNumber": "XXX-XXX-XXXX",
      "CrmSearchOrg": "XXXX",
      "EEList": [
        {
          "AccountID": "xxx-xxxxx-xxxx-xxxxx xxxx-xxxxx",
          "AccountName": "XXXX",
          "AllowanceList": [
            {
              "AllowanceAmount": "327",
              "AllowanceName": "Car Allowance",
              "pxObjClass": "xxxxx-xxxxx-xxxxx"
]

结构2：嵌套Dict 此json位于表和列中JSONTEXT

[
  {
    "OppID": "xxxx-xxxxx",
    "pxObjClass": "xx-xxxxx-xxxx-xxxxxx",
    "pxPages": {
      "EEList": {
        "Country": "xxx",
        "CountryName": "xxx",
        "Currency": "xxx",
        "EstimatedICPCost": "xxxxxxxxxxx",
        "ICPCurrency": "xxxxx",
        "ICPID": "xxxxxxxxx.",
        "ICPNSID": "xxxx-xx",
        "ICPName": "xxx xx xx.",
        "LocalMonthlySalary": "xxxxxx",
        "MinFee": "xxxx",
        "MonthlyGrossCost": "xxxxx",
        "NewOrRepeatCustomer": "xxxxx",
        "OppCloseDate": "xxx-xxx-xx",
        "OppID": "xxx-xxxx",
        "OpportunityName": "xxx - xxx xxx - xxx - xxxx",
        "ReferralSource": "xxxxxx",
        "pxObjClass": "Index-xx-xxxx-xxxx-xxxxxx",
        "pxSubscript": "EEList"
      }
    },
    "pyID": "xxxxxx",
    "pzInsKey": "xxxx-xxxx-xxxx xxxxx-xxx"
  },
]

下面是我的第二个结构的代码

create or replace table xxxx
    as select 
    value:ID::varchar as ID,
    value:caseTypeID::varchar as caseTypeID,
    value:content:AccountID::varchar as AccountID,
    value:content:AccountName::varchar as AccountName,
    value:content:AllKickoffsComplete::boolean as AllKickoffsComplete,
    value:content:ClientCurrency::varchar as ClientCurrency,
    value:content:ClientID::varchar as ClientID,
    value:content:ClientNSID::varchar as ClientNSID,
    value:content:ClientName::varchar as ClientName,
    value:content:CompanyAddressCountryName::varchar as CompanyAddressCountryName,
    value:content:CompanyPhoneNumber::varchar as CompanyPhoneNumber,
    value:content:CreateNew::boolean as CreateNew,
    value:content:CrmSearchOrg::varchar as CrmSearchOrg,
    value:content:EEList:AccountID::varchar as EE_AccountID,
    value:content:EEList:AccountName::varchar as EE_AccountName
from new_raw_json, 
    lateral flatten (input =>jsontext);

这是我尝试过的代码，它只在放入jsontext[n]时有效

select
    value:ID::varchar as ID,
    value:EEListID::varchar as EEListID,
    value:caseTypeID::varchar as caseTypeID
    from new_raw_json,

    lateral flatten (input => jsontext[0]:content:EEList);

谢谢你的帮助

您可以继续分解为嵌套结构（数组中的数组）

明确定义的方法可能以这种方式出现（此处仅投影一些列，以说明级别）：

选择
外部对象。值：caseTypeID作为caseTypeID，
外部对象.value:content.AccountID作为parentAccountID，
eelist_对象。值：AccountID作为eeListAccountID，
容差对象。值：AllowanceName
从…起
新的原始json，
横向展平（输入=>jsontext）外部对象，
横向展平（输入=>外部对象。值：content.EEList）EEList对象，
横向展平（输入=>eelist_对象。值：AllowanceList）余量_对象；

请注意，这只会分解一个已标识的多值路径（

List->EEList->AllowanceList

）。问题不清楚是否必须分解所有路径（如

List->EEList->Addresses AND AllowanceList

），或者是否可以在最终结果中将部分路径存储为

VARIANT

（或其他复杂）类型

---

例如，如果需要为

EEList

下的

Addresses

中列出的每个地址复制

AllowanceList

值，这可以通过从两个分解查询结果执行

连接来实现（一个链接
List->address
，另一个链接
List->EEList->AllowanceList
）.
我认为我的表格第一行的主要问题实际上是一个列表，而不仅仅是一个原始的json。我正在尝试用python重建数据是如何过来的！谢谢你的建议和指导，非常感谢！@Harsh J，你能看一下我的帖子吗？我面临着与雪花相关的问题：