如何在Spring/Hibernate/JPA中正确调用PostgreSQL函数(存储过程)?
我正在使用Spring MVC 4、Hibernate和PostgreSQL 9.3,并在Postgres中定义了如下函数(存储过程):如何在Spring/Hibernate/JPA中正确调用PostgreSQL函数(存储过程)?,spring,hibernate,postgresql,jpa,Spring,Hibernate,Postgresql,Jpa,我正在使用Spring MVC 4、Hibernate和PostgreSQL 9.3,并在Postgres中定义了如下函数(存储过程): CREATE OR REPLACE FUNCTION spa.create_tenant(t_name character varying) RETURNS void AS $BODY$ BEGIN EXECUTE format('CREATE SCHEMA IF NOT EXISTS %I AUTHORIZATION postgr
CREATE OR REPLACE FUNCTION spa.create_tenant(t_name character varying)
RETURNS void AS
$BODY$
BEGIN
EXECUTE format('CREATE SCHEMA IF NOT EXISTS %I AUTHORIZATION postgres', t_name);
END
$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
ALTER FUNCTION spa.create_tenant(character varying)
OWNER TO postgres;
@Override
@Transactional
public void createSchema(String name) {
StoredProcedureQuery sp = em.createStoredProcedureQuery("spa.create_tenant");
sp.registerStoredProcedureParameter("t_name", String.class, ParameterMode.IN);
sp.setParameter("t_name", name);
sp.execute();
}
RETURNS character varying AS
CREATE OR REPLACE FUNCTION spa.create_tenant(t_name character varying)
RETURNS bigint AS
$BODY$
BEGIN
EXECUTE format('CREATE SCHEMA IF NOT EXISTS %I AUTHORIZATION postgres', t_name);
RETURN 1;
END
$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
ALTER FUNCTION spa.create_tenant(character varying)
OWNER TO postgres;
如果我像这样在pgAdmin中运行此函数,它工作正常:
select spa.create_tenant('somename');
现在,我尝试从我的服务运行此函数,如下所示:
CREATE OR REPLACE FUNCTION spa.create_tenant(t_name character varying)
RETURNS void AS
$BODY$
BEGIN
EXECUTE format('CREATE SCHEMA IF NOT EXISTS %I AUTHORIZATION postgres', t_name);
END
$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
ALTER FUNCTION spa.create_tenant(character varying)
OWNER TO postgres;
@Override
@Transactional
public void createSchema(String name) {
StoredProcedureQuery sp = em.createStoredProcedureQuery("spa.create_tenant");
sp.registerStoredProcedureParameter("t_name", String.class, ParameterMode.IN);
sp.setParameter("t_name", name);
sp.execute();
}
RETURNS character varying AS
CREATE OR REPLACE FUNCTION spa.create_tenant(t_name character varying)
RETURNS bigint AS
$BODY$
BEGIN
EXECUTE format('CREATE SCHEMA IF NOT EXISTS %I AUTHORIZATION postgres', t_name);
RETURN 1;
END
$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
ALTER FUNCTION spa.create_tenant(character varying)
OWNER TO postgres;
如果我运行我的方法,我会得到以下错误:
javax.persistence.PersistenceException: org.hibernate.MappingException: No Dialect mapping for JDBC type: 1111
我猜这是因为函数中定义了返回类型void,所以我将返回类型更改为如下所示:
CREATE OR REPLACE FUNCTION spa.create_tenant(t_name character varying)
RETURNS void AS
$BODY$
BEGIN
EXECUTE format('CREATE SCHEMA IF NOT EXISTS %I AUTHORIZATION postgres', t_name);
END
$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
ALTER FUNCTION spa.create_tenant(character varying)
OWNER TO postgres;
@Override
@Transactional
public void createSchema(String name) {
StoredProcedureQuery sp = em.createStoredProcedureQuery("spa.create_tenant");
sp.registerStoredProcedureParameter("t_name", String.class, ParameterMode.IN);
sp.setParameter("t_name", name);
sp.execute();
}
RETURNS character varying AS
CREATE OR REPLACE FUNCTION spa.create_tenant(t_name character varying)
RETURNS bigint AS
$BODY$
BEGIN
EXECUTE format('CREATE SCHEMA IF NOT EXISTS %I AUTHORIZATION postgres', t_name);
RETURN 1;
END
$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
ALTER FUNCTION spa.create_tenant(character varying)
OWNER TO postgres;
如果我再次运行我的方法,则会出现以下异常:
javax.persistence.PersistenceException: org.hibernate.exception.GenericJDBCException: Error calling CallableStatement.getMoreResults
是否有人知道这里发生了什么,以及如何正确调用PostgreSQL中的存储过程,即使返回类型为void?因为您使用的是PostgreSQL,正如您已经编写的,您可以调用
SELECT中的函数类型的任何存储过程(否则,Oracle将只允许您在selects中执行声明为只读的函数)
您可以使用EntityManager.createNativeQuery(SQL)
因为您使用的是Spring,所以可以使用SimpleJdbcTemplate.query(SQL)
执行任何SQL语句。在实体类中,定义一个NamedNativeQuery,就像使用select调用postgresql函数一样
import javax.persistence.NamedNativeQueries;
import javax.persistence.NamedNativeQuery;
import javax.persistence.Entity;
@NamedNativeQueries(
value={
// cast is used for Hibernate, to prevent No Dialect mapping for JDBC type: 1111
@NamedNativeQuery(
name = "Tenant.createTenant",
query = "select cast(create_tenant(?) as text)"
)
}
)
@Entity
public class Tenant
hibernate无法映射void,所以一个解决方法是将结果转换为文本
public void createSchema(String name) {
Query query = em.createNamedQuery("Tenant.createTenant")
.setParameter(1, name);
query.getSingleResult();
}
我认为这是问题的根源。因此,将函数
定义更改如下:
CREATE OR REPLACE FUNCTION spa.create_tenant(t_name character varying)
RETURNS void AS
$BODY$
BEGIN
EXECUTE format('CREATE SCHEMA IF NOT EXISTS %I AUTHORIZATION postgres', t_name);
END
$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
ALTER FUNCTION spa.create_tenant(character varying)
OWNER TO postgres;
@Override
@Transactional
public void createSchema(String name) {
StoredProcedureQuery sp = em.createStoredProcedureQuery("spa.create_tenant");
sp.registerStoredProcedureParameter("t_name", String.class, ParameterMode.IN);
sp.setParameter("t_name", name);
sp.execute();
}
RETURNS character varying AS
CREATE OR REPLACE FUNCTION spa.create_tenant(t_name character varying)
RETURNS bigint AS
$BODY$
BEGIN
EXECUTE format('CREATE SCHEMA IF NOT EXISTS %I AUTHORIZATION postgres', t_name);
RETURN 1;
END
$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
ALTER FUNCTION spa.create_tenant(character varying)
OWNER TO postgres;
将函数更改为返回一些伪值后,将存储过程查询更改为:
StoredProcedureQuery query = entityManager
.createStoredProcedureQuery("spa.create_tenant")
.registerStoredProcedureParameter(1,
Long.class, ParameterMode.OUT)
.registerStoredProcedureParameter(2,
String.class, ParameterMode.IN)
.setParameter(2, name);
query.getResultList();
如果您也在使用spring数据,您可以在@Repository
界面中定义这样一个过程
@Procedure(value = "spa.create_tenant")
public void createTenantOrSomething(@Param("t_name") String tNameOrSomething);
更多信息请参见。如果您想保持简单,只需执行以下操作:
em.createSQLQuery("SELECT * FROM spa.create_tenant(:t_name) ")
.setParameter("t_name", name)").list();
注意,我故意使用list()。出于某种原因。update()对我不起作用。
- PostgreSQL
- 休眠
- Kotlin
您将如何调用JDBC CallableStatement?这就是JPA API的全部内容。如果Hibernate没有反映JDBC提供的内容,那么请尝试其他JPA提供程序,看看它如何处理该查询。该查询不会编译erry@AlexG,因为延迟响应,我已经编辑了实体代码建议,但我希望您已经找到了如何调用函数a的解决方案nd在控制器上获取结果?查看如何调用函数并在控制器上获取结果?查看