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Sql server 2008 SQL Update语句-靠近“的语法错误;设置“;?_Sql Server 2008_Sql Update - Fatal编程技术网

Sql server 2008 SQL Update语句-靠近“的语法错误;设置“;?

Sql server 2008 SQL Update语句-靠近“的语法错误;设置“;?,sql-server-2008,sql-update,Sql Server 2008,Sql Update,我正在根据一些coldfusion逻辑生成下面的sql语句,但它出错了,我似乎找不到原因,我尝试了许多不同的修改,但似乎没有任何帮助 UPDATE MAIN_RECORDS SET JONUM = NULL, SET CUSTNAME = 'Super Sweet Name', SET CONTACTDT = 02/28/2011, SET ENGRECDT = 03/07/2011, SET HOW_WR_DT = 03/07/2011, SET COMM_DT = 03/29/2

我正在根据一些coldfusion逻辑生成下面的sql语句,但它出错了,我似乎找不到原因,我尝试了许多不同的修改,但似乎没有任何帮助

UPDATE MAIN_RECORDS 
SET JONUM = NULL, 
SET CUSTNAME = 'Super Sweet Name', 
SET CONTACTDT = 02/28/2011, 
SET ENGRECDT = 03/07/2011, 
SET HOW_WR_DT = 03/07/2011, 
SET COMM_DT = 03/29/2011, 
SET FACAVALDT = NULL, 
SET FAX_SUPDT = 03/07/2011, 
SET LINENUM = 'CLPRO L6', 
SET POLENUM = 'CLPRO 125 T T3', 
SET REASON = '03/07/11 NO VAC FAC THIS IS THE WRONG INFORMATION IT WAS ON HERE TWICE', 
SET REC_TYPE = 'H', 
SET ORDER_TYPE = 'P', 
SET CANCEL_ORDER = 'Y', 
SET State_abbr = 'IL', 
SET dbfk_state = 17, 
SET xx_streetnumber = '2626', 
SET xx_street = 'Fake St', 
SET xx_city = 'NEWTON', 
SET xx_class_of_service_ind = 'R', 
SET xx_cellphone_ind = '1', 
SET xx_assigned_phone = '3045653897', 
SET xx_exchange_name = 'NEWTON', 
SET XX_new_ref_code = '60', 
SET xx_new_service_type = '11', 
SET ORD_COMDT = 03/11/2011, 
SET delivery_date = NULL 
WHERE ordernum = '08824112' AND exchnum = '304565' 
目前management studio给我的错误是:

Msg 156, Level 15, State 1, Line 1
Incorrect syntax near the keyword 'SET'.

您只需要一个
SET
语句,而不需要多个语句

此外,你的约会日期周围需要有单引号

e、 g:

看看这个声明。帖子中的语法完全错误:)

有关部分:

SET
        { column_name = { expression | DEFAULT | NULL }
        | @variable = expression
        | @variable = column = expression } [ ,...n ] 
请注意,
SET
只能指定一次。
,…n
表示先前的构造(即在
{}
中,可以再指定n次,用逗号分隔:
SET
关键字本身不在该构造内


愉快的编码。

通常情况下,此命令的语法将遵循此逻辑

UPDATE table_name
 SET column1=value, column2=value2,...
 WHERE some_column=some_value

因此,只有一个集合而不是您拥有的多个集合

更新关键字中只需要一个集合来更新n个列-例如:

Update Employee 
set City = Chennai,Country ='India',Employee name = 'Vignesh'
where  Employee Id = 1X234

啊,有时候当你睡眠不足时,简单的事情就会从缝隙中溜走,谢谢你!好的,确保你也在约会前后加上引号。在提交我的答案后,我注意到了这一点。除了引用日期文字,我还建议坚持使用
'yyyymmdd'
,因为根据服务器或用户的语言或区域设置,您使用的格式可能会被误解
'yyyymmdd'
DATETIME
/
SMALLDATETIME
的唯一格式,根据语言/区域设置,该格式保证不会中断。
Update Employee 
set City = Chennai,Country ='India',Employee name = 'Vignesh'
where  Employee Id = 1X234