Sql server 2008 组中具有最大值的特定行

Sql server 2008 组中具有最大值的特定行,sql-server-2008,tsql,max,Sql Server 2008,Tsql,Max,我有以下SQL SERVER表: +--------+-------+-------+------+ | Person | Phone | Count | Rank | +--------+-------+-------+------+ | A | X | 1 | 1 | | B | X | 9 | 2 | | C | X | 5 | 3 | | T | Y | 6 | 1

我有以下SQL SERVER表:

+--------+-------+-------+------+
| Person | Phone | Count | Rank |
+--------+-------+-------+------+
|   A    |   X   |   1   |  1   |
|   B    |   X   |   9   |  2   |
|   C    |   X   |   5   |  3   |
|   T    |   Y   |   6   |  1   |
|   S    |   Y   |   2   |  2   |
+--------+-------+-------+------+
我需要结果为个人电话值,其中排名等于1,但为特定电话的最大计数值,例如:

+--------+-------+----------+------+
| Person | Phone | MaxCount | Rank |
+--------+-------+----------+------+
|   A    |   X   |     9    |  1   |
|   T    |   Y   |     6    |  1   |
+--------+-------+----------+------+
我可以在表上加入两次,但我想知道是否可以使用MAX来实现这一点?

您可以使用
MAX(Count)OVER(电话分区)
,例如使用CTE:

WITH CTE AS
(
    SELECT Person, 
           Phone, 
           MaxCount = MAX(Count)OVER(PARTITION BY Phone), 
           Rank
    FROM dbo.TableName
)
SELECT  Person, 
        Phone, 
        MaxCount, 
        Rank
FROM CTE
WHERE Rank = 1

您可以使用子查询:

SELECT T.Person, T.Phone, (SELECT MAX(Count) 
                           FROM YourTable AS TI 
                           WHERE TI.Phone = T.Phone) AS MaxCount, T.[Rank]
FROM YourTable AS T
WHERE T.[RANK] = 1

另一种解决方案是使用
外部应用
如下:

SELECT Person, 
       Phone, 
       MaxCount,
       [Rank]
FROM YourTable t1
OUTER APPLY (SELECT MAX([count]) AS MaxCount FROM YourTable WHERE Phone = t1.Phone) oa
WHERE [Rank] = 1

您知道您也可以使用
ROW\u NUMBER()OVER(按电话顺序按ID划分)
来获得
排名
“列”?不知道为什么会被否决。。。有什么想法吗?我没有投反对票,我也不知道为什么。