Sql server 选择具有最新CreatedDate的行

我在SQL Server 2014中有一个包含以下列的表：

Type   ProjectNr    CreatedDate   Subject    Body
------------------------------------------------------------------------
101    1000         31-01-2017    12345      Lorem ipsum dolor sit amet
104    1000         31-01-2017    23456      Lorem ipsum dolor sit amet
109    1000         31-01-2017    34567      Lorem ipsum dolor sit amet
109    1000         31-09-2017    45678      Lorem ipsum dolor sit amet
109    1000         31-11-2017    56789      Lorem ipsum dolor sit amet
109    1001         31-10-2017    67890      Lorem ipsum dolor sit amet

我只需要所有类型109与每个项目的最新CreateDate nR

这是需要的结果：

 Type   ProjectNr    CreatedDate   Subject    Body
 -----------------------------------------------------------------------
 109    1000         31-11-2017    56789      Lorem ipsum dolor sit amet
 109    1001         31-10-2017    67890      Lorem ipsum dolor sit amet

行的排序是不必要的

使用密集秩或行编号函数为每个行组按/分区按类型和项目编号以及按CreatedDate列的降序提供行号。然后选择行号为1的行

质疑

试试这个

SELECT Type, ProjectNr, CreatedDate, Subject, Body 
       WHERE Type = 109 and createddate = MAX(CreatedDate) 
       GROUP BY Type, ProjectNr, Subject, Body

如果要对其进行排序，请根据需要添加Order By列

ORDER BY Type, ProjectNr

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您可以用一种更简单的方式：

Select * from [TableName]
where CreatedDate >= '(Your desired date here : YY-MM-DD)'
order by [columnName(if you want them in order)]

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添加[类型]=109@Alex：是的，错过了。。非常感谢。最新答案

ORDER BY Type, ProjectNr

Select * from [TableName]
where CreatedDate >= '(Your desired date here : YY-MM-DD)'
order by [columnName(if you want them in order)]