Sql server 从SQL Server多表查询创建单个XML

我想从SQLServer2005查询多个表，创建一个XML文档，并在存储过程中执行此操作

我知道我可以在一个存储过程中查询多个表，并在.NET应用程序中获得一个可以轻松保存为XML的

DataSet

。但是，我正在尝试在存储过程的上下文中执行类似的操作

基本上我想做这样的事情：

declare @x xml
select @x = x.result
from (select y.* from tabley y for xml path('y')
      union
      select a.* from tablea a for xml path('aa')
     ) as x
select @x

SELECT
    (SELECT y.* FROM dbo.TableY FOR XML PATH('y'), TYPE) AS 'YElements',
    (SELECT a.* FROM dbo.TableA FOR XML PATH('aa'), TYPE) AS 'AElements'
FOR XML PATH(''), ROOT('root')

---

如果您想要一个接一个的，您可以尝试以下方式：

declare @x xml
select @x = x.result
from (select y.* from tabley y for xml path('y')
      union
      select a.* from tablea a for xml path('aa')
     ) as x
select @x

SELECT
    (SELECT y.* FROM dbo.TableY FOR XML PATH('y'), TYPE) AS 'YElements',
    (SELECT a.* FROM dbo.TableA FOR XML PATH('aa'), TYPE) AS 'AElements'
FOR XML PATH(''), ROOT('root')

返回类似以下内容的XML：

<root>
   <YElements>
     <Y>
       ....
     </Y>
     <Y>
       ....
     </Y>
      ......
   </YElements>
   <AElements>
     <A>
       ....
     </A>
     <A>
       ....
     </A>
      ......
   </AElements>
</root>

....
....
......
....
....
......

在sql server中转换表XML

Declare @RESULTXML XML
Declare @SMS_REGISTER TABLE([id] VARCHAR(30),[status] VARCHAR(30))
Declare @EMAIL_REGISTER TABLE([id] VARCHAR(30),[status] VARCHAR(30))
Declare @ODP_REGISTER TABLE([id] VARCHAR(30),[status] VARCHAR(30))

Select @RESULTXML =( 
SELECT (SELECT * FROM @SMS_REGISTER FOR XML PATH('sms'), TYPE) AS 'smss',
         (SELECT * FROM @EMAIL_REGISTER FOR XML PATH('email'), TYPE) AS         'emails',
         (SELECT * FROM @ODP_REGISTER FOR XML PATH('odp'), TYPE) AS 'odps'
    FOR XML PATH('subroot'), ROOT('root') )

像这样返回XML
<root> <subroot> <smss> <sms> <id>NT0000000020</id> <status>registered</status> </sms> <sms> <id>NT0000000021</id> <status>registered</status> </sms> <sms> <id>NT0000000022</id> <status>registered</status> </sms> <sms> <id>NT0000000023</id> <status>registered</status> </sms> </smss> <emails> <email> <id>NT0000000024</id> <status>registered</status> </email> <email> <id>NT0000000025</id> <status>registered</status> </email> </emails> </subroot> </root> 新台币0000000020 登记 NT0000000021 登记 NT0000000022 登记 NT0000000023 登记 NT0000000024 登记 新台币0000000025 登记

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如果我想让它们按相同的顺序排列，该怎么办？