Warning: file_get_contents(/data/phpspider/zhask/data//catemap/7/sql-server/22.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Sql server 水平显示结果_Sql Server_For Xml - Fatal编程技术网

Sql server 水平显示结果

Sql server 水平显示结果,sql-server,for-xml,Sql Server,For Xml,使用SQLServer2005 我希望水平显示itemid、deliverydate、remainpurchapphysical 目前,我正在为XML路径使用,,这很有效 当结果是每个itemid有多个交付日期时,我想让它们显示得更好一些 [ITEMID] [DELIVERYDATE AND REMAINPURCH] ----------------------------------------- [1234] [14/14/2014 25 | 15/15/2015 27

使用SQLServer2005

我希望水平显示
itemid、deliverydate、remainpurchapphysical

目前,我正在为XML路径使用
,这很有效

当结果是每个itemid有多个交付日期时,我想让它们显示得更好一些

  [ITEMID]  [DELIVERYDATE AND REMAINPURCH]
  -----------------------------------------
  [1234]    [14/14/2014 25 | 15/15/2015 27 | 16/16/2016 28]
最好在每个日期之间加上|

这是当前的代码

-select itemid, CONVERT(NVARCHAR, deliverydate, 103),remainpurchphysical
--from purchline where purchstatus =1 --and itemid = '00727-s'
SELECT 
    itemid 
    ,deliverydates = STUFF(
                       (SELECT '   ' + CONVERT(NVARCHAR, deliverydate, 103)
                        FROM purchline b 
                        WHERE b.itemid = a.itemid AND purchstatus = 1 
                        ORDER BY deliverydate 
                        FOR XML PATH('')), 1, 1, '')
    ,remainpurchphysical = STUFF(
                              (SELECT '   ' + CAST(CONVERT(Decimal(9,0), remainpurchphysical) AS VARCHAR)
                               FROM purchline b 
                               WHERE b.itemid = a.itemid AND purchstatus = 1  
                               ORDER BY deliverydate
                               FOR XML PATH('')), 1, 1, '')
FROM purchline a
WHERE purchstatus =1
GROUP BY itemid
ORDER BY itemid
像这样的,

SELECT
     [ITEMID],
     STUFF(
         (SELECT ' | ' + [date]
          FROM Table1
          WHERE [ITEMID] = a.[ITEMID]
          FOR XML PATH (''))
          , 1, 1, '')  AS DateList
FROM Table1 AS a
GROUP BY [ITEMID]

这是当前代码当前代码在哪里?我已经编辑了您的标题。请看“”,其中的共识是“不,他们不应该”。你好,JW,我的数量不在同一领域,我有3个领域。ItemID、交货日期和再采购物理