Sql server 如何在连接多个表时避免重复
该表包含三条记录,见以下临时表:Sql server 如何在连接多个表时避免重复,sql-server,Sql Server,该表包含三条记录,见以下临时表: Declare @TimeStamp table (Id int, SalesMan_ID int, Module_Cdoe varchar(50),Time_In varchar(10),Time_Out varchar(10)) Insert into @TimeStamp values (1,13524,'Analysis','1:30pm','1:40pm'), (2,12543,'Analysis','2:10pm','2:30pm'), (3,12
Declare @TimeStamp table (Id int, SalesMan_ID int, Module_Cdoe varchar(50),Time_In varchar(10),Time_Out varchar(10))
Insert into @TimeStamp values
(1,13524,'Analysis','1:30pm','1:40pm'),
(2,12543,'Analysis','2:10pm','2:30pm'),
(3,12543,'Analysis','3:10pm','3:30pm')
;with cteBase (Seq,Module_Cdoe) as(
Select 1,'Photo' union all
Select 2,'Survey' union all
Select 3,'Merchand'
)
Select id=Row_Number() over (Order By Time_In,SalesMan_id,Seq)
,SalesMan_id
,b.Module_Cdoe
,Time_In
,Time_Out
from @TimeStamp A
Join cteBase B on (A.Module_Cdoe='Analysis')
Order By 1
根据上述查询,结果为:
id SalesMan_id Module_Cdoe Time_In Time_Out
1 13524 Photo 1:30pm 1:40pm
2 13524 Survey 1:30pm 1:40pm
3 13524 Merchand 1:30pm 1:40pm
4 12543 Photo 2:10pm 2:30pm
5 12543 Survey 2:10pm 2:30pm
6 12543 Merchand 2:10pm 2:30pm
7 12543 Photo 3:10pm 3:30pm
8 12543 Survey 3:10pm 3:30pm
9 12543 Merchand 3:10pm 3:30pm
但我需要如下所示:
id SalesMan_id Module_Cdoe Time_In Time_Out
1 13524 Photo 1:30pm 1:40pm
2 13524 Survey 1:30pm 1:40pm
3 13524 Merchand 1:30pm 1:40pm
4 12543 Photo 2:10pm 2:30pm
5 12543 Survey 2:10pm 2:30pm
6 12543 Merchand 2:10pm 2:30pm
(或)
那么,什么样的查询才能达到我的期望呢?根据要求,这只是对原始查询的一个小改动
Declare @TimeStamp table (Id int, SalesMan_ID int, Module_Cdoe varchar(50),Time_In varchar(10),Time_Out varchar(10))
Insert into @TimeStamp values
(1,13524,'Analysis','1:30pm','1:40pm'),
(2,12543,'Analysis','2:10pm','2:30pm'),
(3,12543,'Analysis','3:10pm','3:30pm')
;with cteBase (Seq,Module_Cdoe) as(
Select 0,'Analysis' union all
Select 1,'Photo' union all
Select 2,'Survey' union all
Select 3,'Merchand'
)
, cteDistPop as (
Select Distinct
SalesMan_Id
,Time_In = Max(Time_In)
,Time_Out = Max(Time_Out)
From @TimeStamp
Group By SalesMan_Id
)
Select id=Row_Number() over (Order By Time_In,SalesMan_id,Seq)
,SalesMan_id
,b.Module_Cdoe
,Time_In
,Time_Out
from cteDistPop A
Cross Join cteBase B
Order By 1
返回--在“分析”输入或输出时不清楚。无论哪种方式,您都可以从cteBase中控制它
id SalesMan_id Module_Cdoe Time_In Time_Out
1 13524 Analysis 1:30pm 1:40pm
2 13524 Photo 1:30pm 1:40pm
3 13524 Survey 1:30pm 1:40pm
4 13524 Merchand 1:30pm 1:40pm
5 12543 Analysis 3:10pm 3:30pm <<-- Notice Later Date
6 12543 Photo 3:10pm 3:30pm
7 12543 Survey 3:10pm 3:30pm
8 12543 Merchand 3:10pm 3:30pm
id销售人员\u id模块\u Cdoe时间\u输入时间\u输出时间
113524分析下午1:30 1:40
213524照片下午1:30下午1:40
313524调查下午1:30 1:40
413524商品部下午1:30下午1:40
5 12543分析下午3:10pm 3:30pm根据要求,这只是对原始的一个小的扭曲
Declare @TimeStamp table (Id int, SalesMan_ID int, Module_Cdoe varchar(50),Time_In varchar(10),Time_Out varchar(10))
Insert into @TimeStamp values
(1,13524,'Analysis','1:30pm','1:40pm'),
(2,12543,'Analysis','2:10pm','2:30pm'),
(3,12543,'Analysis','3:10pm','3:30pm')
;with cteBase (Seq,Module_Cdoe) as(
Select 0,'Analysis' union all
Select 1,'Photo' union all
Select 2,'Survey' union all
Select 3,'Merchand'
)
, cteDistPop as (
Select Distinct
SalesMan_Id
,Time_In = Max(Time_In)
,Time_Out = Max(Time_Out)
From @TimeStamp
Group By SalesMan_Id
)
Select id=Row_Number() over (Order By Time_In,SalesMan_id,Seq)
,SalesMan_id
,b.Module_Cdoe
,Time_In
,Time_Out
from cteDistPop A
Cross Join cteBase B
Order By 1
返回--在“分析”输入或输出时不清楚。无论哪种方式,您都可以从cteBase中控制它
id SalesMan_id Module_Cdoe Time_In Time_Out
1 13524 Analysis 1:30pm 1:40pm
2 13524 Photo 1:30pm 1:40pm
3 13524 Survey 1:30pm 1:40pm
4 13524 Merchand 1:30pm 1:40pm
5 12543 Analysis 3:10pm 3:30pm <<-- Notice Later Date
6 12543 Photo 3:10pm 3:30pm
7 12543 Survey 3:10pm 3:30pm
8 12543 Merchand 3:10pm 3:30pm
id销售人员\u id模块\u Cdoe时间\u输入时间\u输出时间
113524分析下午1:30 1:40
213524照片下午1:30下午1:40
313524调查下午1:30 1:40
413524商品部下午1:30下午1:40
512543分析3:10pm 3:30pm试着这样做
Declare @TimeStamp table (Id int, SalesMan_ID int, Module_Code
varchar(50),Time_In varchar(10),Time_Out varchar(10))
Insert into @TimeStamp values
(1,13524,'Analysis','1:30pm','1:40pm'),
(2,12543,'Analysis','2:10pm','2:30pm'),
(3,12543,'Analysis','3:10pm','3:30pm')
第一个预期的表输出
select *From (
Select Row_Number() over (Order By Time_In,SalesMan_id,Seq) id
,SalesMan_id
,b.Module_Code
,Time_In
,Time_Out
,row_number() over (partition by SalesMan_Id,B.Module_code order by id) as rn
from @TimeStamp A
Join (select *from
(values (1,'Photo'),(2,'Survey'),(3,'Merchand'))cteBase(Seq,Module_Code)) B
on (A.Module_Code='Analysis'))t
where rn=1
Order By 1
第二个预期表输出
select *From (
Select Row_Number() over (Order By Time_In,SalesMan_id,Seq) id
,SalesMan_id
,b.Module_Code
,Time_In
,Time_Out
,row_number() over (partition by SalesMan_Id,B.Module_code order by id desc) as rn
from @TimeStamp A
Join (select *from
(values (1,'Photo'),(2,'Survey'),(3,'Merchand'))cteBase(Seq,Module_Code)) B
on (A.Module_Code='Analysis'))t
where rn=1
Order By 1
试着这样,
Declare @TimeStamp table (Id int, SalesMan_ID int, Module_Code
varchar(50),Time_In varchar(10),Time_Out varchar(10))
Insert into @TimeStamp values
(1,13524,'Analysis','1:30pm','1:40pm'),
(2,12543,'Analysis','2:10pm','2:30pm'),
(3,12543,'Analysis','3:10pm','3:30pm')
第一个预期的表输出
select *From (
Select Row_Number() over (Order By Time_In,SalesMan_id,Seq) id
,SalesMan_id
,b.Module_Code
,Time_In
,Time_Out
,row_number() over (partition by SalesMan_Id,B.Module_code order by id) as rn
from @TimeStamp A
Join (select *from
(values (1,'Photo'),(2,'Survey'),(3,'Merchand'))cteBase(Seq,Module_Code)) B
on (A.Module_Code='Analysis'))t
where rn=1
Order By 1
第二个预期表输出
select *From (
Select Row_Number() over (Order By Time_In,SalesMan_id,Seq) id
,SalesMan_id
,b.Module_Code
,Time_In
,Time_Out
,row_number() over (partition by SalesMan_Id,B.Module_code order by id desc) as rn
from @TimeStamp A
Join (select *from
(values (1,'Photo'),(2,'Survey'),(3,'Merchand'))cteBase(Seq,Module_Code)) B
on (A.Module_Code='Analysis'))t
where rn=1
Order By 1
您想显示较早的时间还是较晚的时间。最好指定其中一个。如果你不关心它们,你需要它们吗?如果没有,您可以使用groupingI need the later times更新问题以指定此选项,然后更改id以匹配您的期望值中稍后的行output@AlexandarR好的,从原来的一个小扭曲。我看到分析不见了,“锚”现在是照片吗?你想显示早期还是晚期。最好指定其中一个。如果你不关心它们,你需要它们吗?如果没有,您可以使用groupingI need the later times更新问题以指定此选项,然后更改id以匹配您的期望值中稍后的行output@AlexandarR好的,从原来的一个小扭曲。我看到分析不见了,“锚”现在是照片吗?