Sql server 在Camelcase中添加空格,并在其中添加大写字母
我有一个外部应用程序在camelcase中传递字符串。用户希望报告字符串,并希望将其格式化为句子。字符串中可能包含我需要在其周围添加空格的所有大写字母 基于此问题构建了一个函数: 然而,它并不适用于所有大写字母。下面是我的修改版本Sql server 在Camelcase中添加空格,并在其中添加大写字母,sql-server,tsql,camelcasing,Sql Server,Tsql,Camelcasing,我有一个外部应用程序在camelcase中传递字符串。用户希望报告字符串,并希望将其格式化为句子。字符串中可能包含我需要在其周围添加空格的所有大写字母 基于此问题构建了一个函数: 然而,它并不适用于所有大写字母。下面是我的修改版本 DECLARE @String NVARCHAR(MAX) = 'ThisIsASentenceWithCAPTIInIt' --, @Len INT -- = LEN(@String) , @Delimite
DECLARE @String NVARCHAR(MAX) = 'ThisIsASentenceWithCAPTIInIt'
--, @Len INT -- = LEN(@String)
, @Delimiter CHAR(1) = ' '
, @Iterator INT = 2; --Don't put space to left of first even if it's a capital
WHILE @Iterator <= LEN(@String)
-- Iterate through string
BEGIN
-- Check if current character is Uppercase (lowercase = 0)
IF PATINDEX('[ABCDEFGHIJKLMNOPQRSTUVWXYZ]', SUBSTRING(@String, @Iterator, 1) COLLATE Latin1_General_CS_AI) <> 0
-- Do this if capital
BEGIN
-- check if the previous character is lowercase, if it is then add a space before the current character.
IF(
(PATINDEX('[ABCDEFGHIJKLMNOPQRSTUVWXYZ]', SUBSTRING(@String, @Iterator - 1, 1) COLLATE Latin1_General_CS_AI) = 0
AND SUBSTRING(@String, @Iterator - 1, 1) <> ' '
)
OR PATINDEX('[ABCDEFGHIJKLMNOPQRSTUVWXYZ]', SUBSTRING(@String, @Iterator + 1, 1) COLLATE Latin1_General_CS_AI) = 0)
BEGIN
SET @String = STUFF(@String, @Iterator, 0, @Delimiter);
SET @Iterator+=1;
END;
-- check if the next character is lowercase, if it is then add a space before the current character.
SET @Iterator+=1;
END;
---- Don't care about current character being lowercase. Just continue iterating
SET @Iterator+=1;
END;
SELECT @String;
我从应用程序中获得的示例-此为CaptiInit语句
我想传回的是——这是一个有CAPTI的句子
我从修改后的版本中得到的是—这是一个带有CAPTIIn It的内容在SQL Server中执行此操作不是最佳选择。此外,重写现有字符串可能会有些困难 我认为有更多的方法来简化这段代码,但我相信这是一个版本,它将实现您所期望的结果
DECLARE @String NVARCHAR(MAX) = 'ThisIsASentenceWithCAPTIInIt'
--, @Len INT -- = LEN(@String)
, @Delimiter CHAR(1) = ' '
, @Iterator INT = 1; --Don't put space to left of first even if it's a capital
DECLARE @retval nvarchar(max) = '';
WHILE @Iterator <= LEN(@String)
-- Iterate through string
BEGIN
-- Check if current character is Uppercase (lowercase = 0)
IF PATINDEX('[ABCDEFGHIJKLMNOPQRSTUVWXYZ]', SUBSTRING(@String, @Iterator, 1) COLLATE Latin1_General_CS_AI) <> 0
-- Do this if capital
BEGIN
-- check if the previous character is lowercase, if it is then add a space before the current character.
IF(
(PATINDEX('[ABCDEFGHIJKLMNOPQRSTUVWXYZ]', SUBSTRING(@String, @Iterator - 1, 1) COLLATE Latin1_General_CS_AI) = 0
AND SUBSTRING(@String, @Iterator - 1, 1) <> ' '
)
OR PATINDEX('[ABCDEFGHIJKLMNOPQRSTUVWXYZ]', SUBSTRING(@String, @Iterator + 1, 1) COLLATE Latin1_General_CS_AI) = 0)
BEGIN
set @retval += ' ' ;
--SET @String = STUFF(@String, @Iterator, 0, @Delimiter);
--SET @Iterator+=1;
END;
-- check if the next character is lowercase, if it is then add a space before the current character.
--Set @retval += SUBSTRING(@String, @Iterator, 1);
--SET @Iterator+=1;
END;
---- Don't care about current character being lowercase. Just continue iterating
Set @retval += SUBSTRING(@String, @Iterator, 1);
SET @Iterator+=1;
END;
SET @retval = Ltrim(@retval);
SELECT @retval;
在SQL Server中执行此操作不是最佳选择。此外,重写现有字符串可能会有些困难 我认为有更多的方法来简化这段代码,但我相信这是一个版本,它将实现您所期望的结果
DECLARE @String NVARCHAR(MAX) = 'ThisIsASentenceWithCAPTIInIt'
--, @Len INT -- = LEN(@String)
, @Delimiter CHAR(1) = ' '
, @Iterator INT = 1; --Don't put space to left of first even if it's a capital
DECLARE @retval nvarchar(max) = '';
WHILE @Iterator <= LEN(@String)
-- Iterate through string
BEGIN
-- Check if current character is Uppercase (lowercase = 0)
IF PATINDEX('[ABCDEFGHIJKLMNOPQRSTUVWXYZ]', SUBSTRING(@String, @Iterator, 1) COLLATE Latin1_General_CS_AI) <> 0
-- Do this if capital
BEGIN
-- check if the previous character is lowercase, if it is then add a space before the current character.
IF(
(PATINDEX('[ABCDEFGHIJKLMNOPQRSTUVWXYZ]', SUBSTRING(@String, @Iterator - 1, 1) COLLATE Latin1_General_CS_AI) = 0
AND SUBSTRING(@String, @Iterator - 1, 1) <> ' '
)
OR PATINDEX('[ABCDEFGHIJKLMNOPQRSTUVWXYZ]', SUBSTRING(@String, @Iterator + 1, 1) COLLATE Latin1_General_CS_AI) = 0)
BEGIN
set @retval += ' ' ;
--SET @String = STUFF(@String, @Iterator, 0, @Delimiter);
--SET @Iterator+=1;
END;
-- check if the next character is lowercase, if it is then add a space before the current character.
--Set @retval += SUBSTRING(@String, @Iterator, 1);
--SET @Iterator+=1;
END;
---- Don't care about current character being lowercase. Just continue iterating
Set @retval += SUBSTRING(@String, @Iterator, 1);
SET @Iterator+=1;
END;
SET @retval = Ltrim(@retval);
SELECT @retval;
我的建议是:
DECLARE @s VARCHAR(100)='ThisIsASentenceWithCAPTIInIt';
WITH cte AS
(
SELECT 1 AS Position
,@s AS Original
,CAST(SUBSTRING(@s,1,1) AS VARCHAR(MAX)) AS GrowingString
UNION ALL
SELECT cte.Position+1
,cte.Original
,CONCAT(cte.GrowingString
,CurrentLetter
,CASE WHEN CurrentCapit=0 AND NextCapit=1 THEN ' ' ELSE
CASE WHEN CurrentCapit=1 AND NextCapit=1 AND ThirdCapit=0 THEN ' ' ELSE '' END END ) AS GrowingString
FROM cte
CROSS APPLY(SELECT SUBSTRING(@s,cte.Position+1,1) CurrentLetter
,SUBSTRING(@s,cte.Position+2,1) NextLetter
,SUBSTRING(@s,cte.Position+3,1)ThirdLetter) A
CROSS APPLY(SELECT CASE WHEN ASCII(CurrentLetter) BETWEEN 65 AND 90 THEN 1 ELSE 0 END CurrentCapit
,CASE WHEN ASCII(NextLetter) BETWEEN 65 AND 90 THEN 1 ELSE 0 END NextCapit
,CASE WHEN ASCII(ThirdLetter) BETWEEN 65 AND 90 THEN 1 ELSE 0 END ThirdCapit) B
WHERE cte.Position < LEN(@s)
)
SELECT TOP 1 GrowingString
FROM cte
ORDER BY Position DESC;
简而言之:
我们使用递归CTE。这个简单的方法只需逐个字符读取字符串,并在末尾以growinString的形式返回整个字符串。这将与原始字符串相同
棘手的部分是:在哪里插入空格
如果当前字母未大写,而下一个字母大写,则需要一个空格。那是肯定的。此外,嵌入的CASE将测试当前和下一个字母是否大写,但第三个字母是否大写。在这种情况下,我们也需要空间。这是我的建议:
DECLARE @s VARCHAR(100)='ThisIsASentenceWithCAPTIInIt';
WITH cte AS
(
SELECT 1 AS Position
,@s AS Original
,CAST(SUBSTRING(@s,1,1) AS VARCHAR(MAX)) AS GrowingString
UNION ALL
SELECT cte.Position+1
,cte.Original
,CONCAT(cte.GrowingString
,CurrentLetter
,CASE WHEN CurrentCapit=0 AND NextCapit=1 THEN ' ' ELSE
CASE WHEN CurrentCapit=1 AND NextCapit=1 AND ThirdCapit=0 THEN ' ' ELSE '' END END ) AS GrowingString
FROM cte
CROSS APPLY(SELECT SUBSTRING(@s,cte.Position+1,1) CurrentLetter
,SUBSTRING(@s,cte.Position+2,1) NextLetter
,SUBSTRING(@s,cte.Position+3,1)ThirdLetter) A
CROSS APPLY(SELECT CASE WHEN ASCII(CurrentLetter) BETWEEN 65 AND 90 THEN 1 ELSE 0 END CurrentCapit
,CASE WHEN ASCII(NextLetter) BETWEEN 65 AND 90 THEN 1 ELSE 0 END NextCapit
,CASE WHEN ASCII(ThirdLetter) BETWEEN 65 AND 90 THEN 1 ELSE 0 END ThirdCapit) B
WHERE cte.Position < LEN(@s)
)
SELECT TOP 1 GrowingString
FROM cte
ORDER BY Position DESC;
简而言之:
我们使用递归CTE。这个简单的方法只需逐个字符读取字符串,并在末尾以growinString的形式返回整个字符串。这将与原始字符串相同
棘手的部分是:在哪里插入空格
如果当前字母未大写,而下一个字母大写,则需要一个空格。那是肯定的。此外,嵌入的CASE将测试当前和下一个字母是否大写,但第三个字母是否大写。在这种情况下,我们也需要空间。在我看来,SQL Server并不是最好的选择。您最好使用CLR或应用程序来执行此操作。此外,发布您的SQL Server版本也是值得的。在我看来,SQL Server并不是最佳选择。您最好使用CLR或应用程序来执行此操作。此外,发布您的SQL Server版本也是值得的。与我所做的相比,这是非常有效的。谢谢与我所做的相比,这是非常有效的。谢谢