Sql server SQL Server 2008中需要计数查询

我的表名是abc，我想按日期和状态排列数据，其中按日期排列的计数为on，按日期排列的计数为off

ID          Time                    Status
----------- ----------------------- --------------------------------------------------
1           2013-12-24 00:00:00     on
2           2013-12-25 00:00:00     on
3           2013-12-26 00:00:00     on
4           2013-12-27 00:00:00     on
5           2013-12-28 00:00:00     on
6           2013-12-29 00:00:00     on
7           2013-12-30 00:00:00     on
8           2013-12-31 00:00:00     on
9           2013-12-24 00:00:00     off
10          2013-12-25 00:00:00     off
11          2013-12-27 00:00:00     off
12          2013-12-27 00:00:00     on
13          2013-12-27 00:00:00     off
14          2013-12-27 00:00:00     on
15          2013-12-27 00:00:00     off
16          2013-12-28 00:00:00     on
17          2013-12-28 00:00:00     off
18          2013-12-28 00:00:00     on
19          2013-12-29 00:00:00     off
20          2013-12-29 00:00:00     on
21          2013-12-30 00:00:00     off
22          2013-12-30 00:00:00     on
23          2013-12-30 00:00:00     off
24          2013-12-30 00:00:00     on
25          2013-12-30 00:00:00     off
26          2013-12-31 00:00:00     on
27          2013-12-31 00:00:00     off
28          2013-12-31 00:00:00     on
29          2013-12-31 00:00:00     off
30          2013-12-31 00:00:00     on
31          2013-12-31 00:00:00     off

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像这样的东西怎么样

Select time, SUM(on_cnt),SUM(off_cnt) FROM
(select time,[on] as on_cnt,[off] as off_cnt from table1
pivot 
(
 count(Status)
 for Status in ([on],[off])
) as p) as st
GROUP BY time

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请不要交叉张贴：这是好的和有效的，但它会重复日期，就像它只会重复日期，如果它也有时间部分，从你的例子它没有。那么它有时间部分吗？好的，我明白，是的，它有不同的时间，你是对的，我怎么能删除时间部分？现在就开始吧。因此，类似于

CAST（[Time]AS Date）DateOnly的功能非常有效，但是它使用了3个连接，这不是减少连接数量的任何方法吗？现在检查。消除连接
SELECT 
[Time], 
SUM(CASE WHEN [Status] = 'On' THEN 1 ELSE 0 END) CntON,
SUM(CASE WHEN [Status] = 'Off' THEN 1 ELSE 0 END) CntOff
FROM Table
GROUP BY [Time]