Sql server 尝试对子查询的前1项求和
下面是我的SELECT语句的一小部分:Sql server 尝试对子查询的前1项求和,sql-server,sql-server-2008,Sql Server,Sql Server 2008,下面是我的SELECT语句的一小部分: SELECT CASE WHEN I.IsSimCheckout=1 THEN SUM(DISTINCT SalePrice) ELSE SUM(SalePrice) END FROM InvoiceDetail TD WHERE TD.InvoiceID = D.InvoiceID 我想做的是: SELECT CASE WHEN I.IsSimCheckout=1 THEN SUM(TOP 1 SalePrice ORDER BY
SELECT CASE WHEN I.IsSimCheckout=1 THEN
SUM(DISTINCT SalePrice) ELSE SUM(SalePrice) END
FROM InvoiceDetail TD WHERE TD.InvoiceID = D.InvoiceID
我想做的是:
SELECT CASE WHEN I.IsSimCheckout=1 THEN
SUM(TOP 1 SalePrice ORDER BY SalePrice) + SUM(TOP 1 SalePrice ORDER BY SalePrice DESC) ELSE SUM(SalePrice) END
FROM InvoiceDetail TD WHERE TD.InvoiceID = D.InvoiceID
显然,我知道后一种SQL不会编译。但基本上,我想做的是,如果I.IsSimCheckout等于1,那么我想把最高售价和最低售价相加,而不是把它们相加。希望我所做的是有意义的,并且是清楚的
我正在使用SQLServer2008
SELECT
....
FROM InvoiceDetail TD
OUTER APPLY
(
SELECT TOP 1 SalePrice
FROM D(?)
WHERE TD.InvoiceID = D.InvoiceID
ORDER BY SalePrice ASC
) LP
OUTER APPLY
(
SELECT TOP 1 SalePrice
FROM D(?)
WHERE TD.InvoiceID = D.InvoiceID
ORDER BY SalePrice DESC
) HP
WHERE TD.InvoiceID = D.InvoiceID
这是总的想法。我将为您保留SELECT语句。您可以使用groupby按如下方式执行此操作
select
case when I.IsSimCheckout=1 then max(id.SalePrice)+min(id.SalePrice)
else sum(id.SalePrice) as result
from Invoice I join InvoiceDetail ID on I.InvoiceID=Id.InvoiceID
group by i.InvoiceID, id.InvoiceID, I.IsSimCheckout
请回顾您的问题并给出明确的方式