Sql server 获取两个特定字符之间的字符串
我有一个包含文本数据的Filetext列的表fileslistSql server 获取两个特定字符之间的字符串,sql-server,sql-server-2008,sql-server-2008-r2,Sql Server,Sql Server 2008,Sql Server 2008 R2,我有一个包含文本数据的Filetext列的表fileslist create table fileslist ( FileID int identity (1,1), Filetext nvarchar(max) ) insert into fileslist select 'this file(''SQL_SCALAR1'') has been created to test your tricks of (''SQL_SCALAR2'')' insert into
create table fileslist
(
FileID int identity (1,1),
Filetext nvarchar(max)
)
insert into fileslist select 'this file(''SQL_SCALAR1'') has been created to test your tricks of (''SQL_SCALAR2'')'
insert into fileslist select 'this file(''SCALAR3'') created to test your tricks of (''SQL_SCALAR4'')'
insert into fileslist select 'this file(''SQL_SCALAR5'') has been created to test your tricks of (''SQL_SCALAR6'')'
insert into fileslist select 'this file(''SQL_7'') has been created'
insert into fileslist select 'this file(''SQL_SCALAR8'') has been created to test your tricks of (''SQL_SCALAR9''), ohh i have more text than other (''SQL_SCALAR10'')files'
我需要帮助来逐个读取所有记录,以提取两个特定字符“(“and”)之间的字符串,并且输出应该是
SQL_SCALAR1
SQL_SCALAR2
SCALAR3
SQL_SCALAR4
SQL_SCALAR5
SQL_SCALAR6
SQL_7
SQL_SCALAR8
SQL_SCALAR9
SQL_SCALAR10
我选择这种方法的原因是,它可以很好地处理您正在搜索的动态模式数(每行) 首先,我会使用杰夫·摩登的字符串拆分器
/*
* Jeff Moden's famous string spliiter
* http://www.sqlservercentral.com/articles/Tally+Table/72993/
*/
CREATE FUNCTION [dbo].[DelimitedSplit8K]
--===== Define I/O parameters
(@pString VARCHAR(8000), @pDelimiter CHAR(1))
--WARNING!!! DO NOT USE MAX DATA-TYPES HERE! IT WILL KILL PERFORMANCE!
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
--===== "Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000...
-- enough to cover VARCHAR(8000)
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT 1 UNION ALL
SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
),
cteLen(N1,L1) AS(--==== Return start and length (for use in substring)
SELECT s.N1,
ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000)
FROM cteStart s
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
Item = SUBSTRING(@pString, l.N1, l.L1)
FROM cteLen l
;
然后,我会写以下内容
SELECT SUBSTRING (
Item,
2,
CHARINDEX(')', Item) - 3
)
FROM FilesList
CROSS
APPLY [dbo].[DelimitedSplit8K](FileText, '(')
WHERE Item LIKE '''SQL%'
根据评论中的要求;(以这种方式杀掉Jeff的代码,我一点也不激动…)
使用方法如下:
SELECT *
FROM FilesList
CROSS
APPLY [dbo].[DelimitedSplit8K_Butchered](FileText, '(', ')')
不确定要如何显示
SELECT SUBSTRING ( (LEFT(@ss,CHARINDEX(')',@ss) - 1)),CHARINDEX('(',@ss)+1,LEN(LEFT(@ss,CHARINDEX(')',@ss) - 1))),
SUBSTRING ((RIGHT(@ss,CHARINDEX('(',REVERSE(@ss)) - 1)),1,LEN(RIGHT(@ss,CHARINDEX('(',REVERSE(@ss)) - 1))-1)
或
这就是你想要的解决方案,加油
;WITH CTE AS
(
SELECT SUBSTRING(FILETEXT,CHARINDEX('(',FileText,1)+2,11) 'Result'
FROM FILESLIST
UNION ALL
SELECT * FROM
(
SELECT
SUBSTRING(
(SUBSTRING(FILETEXT,CHARINDEX(')',FILETEXT,1)+1,LEN(FILETEXT)-
CHARINDEX(')',FILETEXT,1)) )
,CHARINDEX('(',(SUBSTRING(FILETEXT,CHARINDEX(')',FILETEXT,1)+1,LEN(FILETEXT)-
CHARINDEX(')',FILETEXT,1)) ) ,1)+2,11
) 'Result'
FROM FILESLIST
) T1
WHERE Result like '%SQL%'
)
SELECT * FROM CTE
ORDER BY RESULT ASC
使用递归
CTE
的解决方案是
WITH REP AS (
SELECT FileID
, Filetext = REPLACE(Filetext, ')', '(')
FROM fileslist
), Splitter AS (
SELECT FileID
, FileText
, NextStart = CHARINDEX('(', FileText)
, Pos = 0
, Token = CAST(SubString(FileText, 0, CHARINDEX('(', FileText))
AS NVarchar(50))
FROM REP
UNION ALL
SELECT FileId
, FileText
, NextStart = CHARINDEX('(', FileText, NextStart + 1)
, Pos = Pos + 1
, Token = CAST(SubString(FileText, NextStart + 1
, CHARINDEX('(', FileText, NextStart + 1)
- NextStart - 1) AS NVarchar(50))
FROM Splitter
WHERE CHARINDEX('(', FileText, NextStart + 1) - NextStart - 1 > 0
)
SELECT FileID, Token
FROM REC
WHERE Pos % 2 = 1
order by FileID, Pos
Splitter
CTE
使用单个分隔符分割行,因此在使用它之前,我们需要使两个分隔符相同。主查询只返回奇数标记,因为偶数标记是字符串的另一部分,例如字符串“此文件(“SQL_7”)已创建”
将由拆分器返回(仅包含感兴趣的列):
使用此查询我们无法获取SQL\u SCALAR2、SQL\u SCALAR4、SQL\u SCALAR6Ah。。。很抱歉-我将调整标记这是否可能我们可以创建一个表值函数,该函数接受输入“(”and“)”,并返回这些字符之间的所有字符串,这些字符串可能不像“''SQL%”或固定数量的字符,我对我的问题做了修改是的-将在我的答案中放置更新我的答案-很抱歉误解。这是一个很好的例子
SELECT SUBSTRING ( (LEFT(@ss,CHARINDEX(')',@ss) - 1)),CHARINDEX('(',@ss)+1,LEN(LEFT(@ss,CHARINDEX(')',@ss) - 1)))
Union
SELECT SUBSTRING ((RIGHT(@ss,CHARINDEX('(',REVERSE(@ss)) - 1)),1,LEN(RIGHT(@ss,CHARINDEX('(',REVERSE(@ss)) - 1))-1)
;WITH CTE AS
(
SELECT SUBSTRING(FILETEXT,CHARINDEX('(',FileText,1)+2,11) 'Result'
FROM FILESLIST
UNION ALL
SELECT * FROM
(
SELECT
SUBSTRING(
(SUBSTRING(FILETEXT,CHARINDEX(')',FILETEXT,1)+1,LEN(FILETEXT)-
CHARINDEX(')',FILETEXT,1)) )
,CHARINDEX('(',(SUBSTRING(FILETEXT,CHARINDEX(')',FILETEXT,1)+1,LEN(FILETEXT)-
CHARINDEX(')',FILETEXT,1)) ) ,1)+2,11
) 'Result'
FROM FILESLIST
) T1
WHERE Result like '%SQL%'
)
SELECT * FROM CTE
ORDER BY RESULT ASC
WITH REP AS (
SELECT FileID
, Filetext = REPLACE(Filetext, ')', '(')
FROM fileslist
), Splitter AS (
SELECT FileID
, FileText
, NextStart = CHARINDEX('(', FileText)
, Pos = 0
, Token = CAST(SubString(FileText, 0, CHARINDEX('(', FileText))
AS NVarchar(50))
FROM REP
UNION ALL
SELECT FileId
, FileText
, NextStart = CHARINDEX('(', FileText, NextStart + 1)
, Pos = Pos + 1
, Token = CAST(SubString(FileText, NextStart + 1
, CHARINDEX('(', FileText, NextStart + 1)
- NextStart - 1) AS NVarchar(50))
FROM Splitter
WHERE CHARINDEX('(', FileText, NextStart + 1) - NextStart - 1 > 0
)
SELECT FileID, Token
FROM REC
WHERE Pos % 2 = 1
order by FileID, Pos
Pos | Token
----+------------------
0 | this file
1 | SQL_7
2 | has been created